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erastovalidia [21]
3 years ago
10

An angle bisector of a triangle divides the opposite side of the triangle into segments 6 cm and 5 cm long. A second side of the

triangle is 6.9 cm long. Find the longest and shortest possible lengths of the third side of the triangle. Round answers to the nearest tenth of a centimeter.
Mathematics
1 answer:
sveticcg [70]3 years ago
6 0
<span>Based in the information given in the problem, you must apply the The Angle Bisector Theorem. Let's call the triangle: "ABC"; the internal bisector of the angle that divides its opposite side: "AP"; and "x": the longest and shortest possible lengths of the third side of the triangle.

 If BP= 6 cm and CP= 5 cm, we have:

 BP/CP = AB/AC

 We don't know if second side of the triangle (6.9 centimeters long) is AB or AC, so:

 1. If AB = 6.9 cm and AC = x:
 6/5 = 6.9/x
 x = (5x6.9)/6
 x = 5.80 cm

 2. If AC= 6.9 cm and AB= x:
 6/5 = x/6.9
 x = 6.9x6/5
 x = 8.30 cm

 Then, the answer is: 
 The longest possible length of the third side of the triangle is 8.30 cm and the and shortest length of it is 5.80 cm.</span>


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Complete Question

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Answer:

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Step-by-step explanation:

From the question we are told that  

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Generally given that there was no prior knowledge about the proportion of who might support the law, we will assume the sample proportion to be  

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From the question we are told the confidence level is  90% , hence the level of significance is    

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=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

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Generally the sample size is mathematically represented as  

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=>   n = [\frac{1.645 }{0.05} ]^2 * 0.5 (1 - 0.5 )

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Step-by-step explanation:

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2 years ago
The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand
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Answer with Step-by-step explanation:

We are given that

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Using binomial theorem nC_r(1-p)^{n-r}p^r

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Answer:

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given data

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substituting our data to find n

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Answer:

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Therefore, Edgardo would use the container 160 times to fill.

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