We can display the information given as an equation:
2000 *

= 4000; r = increase per annum
Now, we rearrange and solve for r:

= 2
r =
![\sqrt[19]{2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B19%5D%7B2%7D%20)
= 1.037.....
We can now work out the increase for 5 years like so:
2000 *

= 2400.205..... ⇒
$2400
P = 2(L + W)
P = 22
L = 2W + 2
22 = 2(2W + 2 + W)
22 = 2(3W + 2)
22 = 6W + 4
22 - 4 = 6W
18 = 6W
18/6 = W
3 = W.....this is the width
L = 2W + 2
L = 2(3) + 2
L = 6 + 2
L = 8 meters <=== this is the length
Answer:

Step-by-step explanation:
By definition we know that

and

As 
Then

Now square both sides of the equation:



In the second quadrant sin (t) is positive. Then we take the positive root


,make y the subject
2y=b-4x
divide all sides by 2
y=b\2-4x\2
Answer:
perimeter = 322.5 ft ( to the nearest tenth of a foot)
Step-by-step explanation:
Length the length of the sides of the square be L
Area of a square = L²
∴ 6,500 = L²
L = √(6,500)
L = 80.6226
Next Let us calculate the perimeter
Perimeter of a square = L + L + L + L = 4L
perimeter = 4 × 80.6226
Perimeter = 322.4904 ft
perimeter = 322.5 ft ( to the nearest tenth of a foot)
<em>N:B rounding to the nearest tenth of a foot is same as rounding to 1 decimal place.</em>