Problem 10 / (Second Session 2006)
1 answer:
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Answer:
Option B is correct.
Step-by-step explanation:
We have given a triangle ABC and EDC please look at the figure
We can see that AE and BD are transversal therefore, ∠EAB=∠AED being alternate interior angles
And ∠ACB=∠DCE are vertically opposite angles hence, equal
So, by AA similarity postulate the above to triangles are similar
ΔABC ΔEDC
Therefore, Option B is correct that is Triangle ABC is similar to triangle EDC , because m∠3 = m∠4 and m∠1 = m∠5
NOTE: m∠3 = m∠4 corresponds to m∠ACB=m∠DCE
And m∠1 = m∠5 corresponds to m∠EAB=m∠AED
The graph that matches the given equation is y≥x-1 is Graph A.
Option: C.
<u>Step-by-step explanation:</u>
The given equation y≥x-1 is a linear inequality equation.
Graphing Linear Inequalities differs from graphing regular linear equations. That is it has certain rules to be followed to draw the graph.
- First, rearrange the equation as y in the left and other terms in the opposite side.
- Check for the line: y= , y≤ and y≥ comes with straight line where as y< and y> comes with a dotted line.
- Shading: If y> greater than or y≥ greater than or equal is present then the space above the line has to be shaded. If y< less than or y≤ less than or equal is present then the space below the line has to be shaded.
For the given equation y≥x-1,
The line will be solid passing through (0,-1) and (3,2) since it has y≥. Also, the region above the line is shaded.
So the graph A is the graph that matches the equation y≥x-1.
