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3 years ago

What is the LCD of 1/4a and 5/6a ? 12a 24a^2 12a^2 24a

Mathematics

2 answers:

faust18 [17]3 years ago

8 0

1/(4a) & 5/(6a)

(3)(1/4a)=3/12a

(2)(5/6a)=10/12a

LCD=12a

larisa [96]3 years ago

4 0

Answer:

Step-by-step explanation:

The least common divisor refers to the smallest common number that multiplies all of them, so in this case, the Least Common Factor is

4 6 | 2

2 3 | 2

1 3 | 3

1 1

So, the LCD is $2 \times 2 \times 3 =12$ , and the variable would be just <em>a</em>, because it's already the least possible one.

Theferefore, the LCD is 12a

In the process to obtain the LCD we just separated each number in their prime factors.

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If y = 124 and x = 12, find y when x = -24.

tatyana61 [14]

Answer:

y = -248

Step-by-step explanation:

Hi there!

Set up a proportion:

$\displaystyle\frac{124}{12} =\frac{y}{-24}$

Cross-multiply:

$12y=(-24)(124)\\12y=-2976\\y=-248$

I hope this helps!

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3 years ago

Right isosceles triangles are constructed on the sides of a 3−4−5 right triangle, as shown. A capital letter represents the area

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Answer:

Step-by-step explanation:

because the triangles are isosceles, that means that the area of Z is 5x5x1/2, which equals 12.5

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3 years ago

Suppose you are given a cube made of magnesium (mg) metal of edge length 2.15 cm. (a) calculate the number of mg atoms in the cu

SVETLANKA909090 [29]

solution:

a) To calculate the volume of cube of edge 1.0cm

Volume= (edge)³

=(100cm) ³

= 1cm³

To find the mass of MG atoms

Density = mass/volume

Mass of mg = 1.74g/cm³ x 1cm³

= 1.74g

To find the number of mg atoms,

Molar mass of mg = 24.31g

24.31g mg contain 6.022 x 10²³ atoms of mg

1.74g mg contain = 6.022 x 10²³mg atoms/24.31g mg x 1.74g mg

= 0.4310 x 10²³mg atoms

= 4.31 x 10²² mg atoms

B) to find the volume occupied by mg atoms

Total volume of cube = 1 cm³

Volume occupied by mg atoms

= 74% of 1cm³

=74/100 x 1cm³= 0.74cm³

To find the volume of 1 mg atom

4.31 x 10²² mg atoms occupy 0.74 cm³

1 atom will occupy 0.74cm³

1 atom will occupy = 0.74cm³/4.31 x 10²²mg atoms x 1mg atom

volume of 1 mg atom = 0.1716 x 10⁻²²cm²

Volume of 1 mg atom = 4/3 π³ in the form of sphere.

4/3πr³ = 0.1716 x 10⁻²²cm³

R³ = 0.1716 x 10⁻²²cm³x 4/3 x 7/22

R³ = 0.04095 x 10⁻²²cm³

R = 0.1599 x 10⁻⁷cm

1 = 10⁻¹⁰cm

= 0.1599 x 10⁻⁷cm

= 1pm/1 x 10⁻¹⁰cm x 0.1599 x 10-7cm

= 1.599 x 10² pm

R= 1.6 x 10²pm

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qwelly [4]

Answer:

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