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schepotkina [342]
4 years ago
11

A tree 63 ft high casts a 38 ft shadow. How tall is a tree that casts a 52 ft shadow at the same time of the day? (to the neares

t tenth
Mathematics
1 answer:
Mrac [35]4 years ago
3 0
52/38 = 1.368

1.368 x 63 = 86.21

tree is 86.2 feet high
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lbvjy [14]
I think the answer is -7/4.
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The midpoint of CD is M(-1,-2). One endpoint is C (-9,-4). Find the coordinates of the other endpoint D.
yan [13]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&C&(~ -9 &,& -4~) 
%  (c,d)
&D&(~ x &,& y~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{x-9}{2}~~,~~\cfrac{y-4}{2} \right)=\stackrel{midpoint~M}{(-1~~,~~-2)}\implies 
\begin{cases}
\cfrac{x-9}{2}=-1\\\\
x-9=-2\\
\boxed{x=7}\\
----------\\
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y-4=-4\\
\boxed{y=0}
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6 0
3 years ago
if you could generate energy by fusing the hydrogen in solution a, how much of the solution would you need to generate the elect
iogann1982 [59]

Answer:

We know that:

Energy released by fusion of hydrogen in 1 liter of solution A = 7.6x10^10 J

Energy used daily in a certain family home = 3x10^4 J

(you did not write the units, so i suppose that are the same in both cases)

Then, if x is the number of liters of solution A used, the energy produced will be:

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And we want this equal to 3x10^4

then:

E(x) = x*7.6x10^10 J = 3x10^4 j

now we solve this for x.

x = (3x10^4 j)/(7.6x10^10 j) = 3.9x10^-7

Then you need to use 3.9x10^-7 L of solution a.

4 0
3 years ago
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Novosadov [1.4K]

Answer:

I=PRT 9.5% in decimal form is .095=11 times rate times tax but we don't know what the tax is.

6 0
3 years ago
Given the function g(x) = x2 - 4x + 0, determine the average rate of change of
kozerog [31]

Answer:

4

Step-by-step explanation:

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24/6 = 4

3 0
3 years ago
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