Help me please! ill give brainliest
1 answer:
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Step-by-step explanation:
2 : 3 = 6 : x ,
Ratio can be written as
2*3 = 6, we multiply top and bottom of fraction by 3
So value of x=9
4 : 7 = x : 42 ,
7*6 = 42, we multiply top and bottom of fraction by 6
So value of x=24
2x : 48 = 3 : 12,
\frac{3}{12}[/tex] =
2x= 12, so x= 6
12 : 15 = x : 20
,
we multiply top and bottom by 4/3
So value of x=16
Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
