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Elan Coil [88]
3 years ago
14

Help me, select all that apply

Mathematics
1 answer:
Burka [1]3 years ago
4 0

Answer:

1.5ft, 2ft, 2.5ft

12ft, 35ft, 37ft

Step-by-step explanation:

You might be interested in
Given: ABCD trapezoid<br> BC=1.2m, AD=1.8m<br> AB=1.5m, CD=1.2m<br> AB∩CD=K<br> Find: BK and CK
stepladder [879]

Answer:

The value of BK is 3m and the value of CK is 2.4m.

Step-by-step explanation:

Given information: ABCD trapezoid

, BC=1.2m, AD=1.8m

, AB=1.5m, CD=1.2m

, AB∩CD=K.

Using the given information draw a figure.

Two sides of a trapezoid are parallel.

Since AB∩CD=K, therefore AB and CD are not parallel, because parallel line never intersect.

AD\parallelBC

\angle KBC=\angle KAD              (Corresponding angles)

\angle KCB=\angle KDA             (Corresponding angles)

By AA rule of similarity

\triangle KBC\sim \triangle KAD

Corresponding sides of similar triangles are proportional.

\frac{KB}{KA}=\frac{KC}{KD}=\frac{BC}{AD}

\frac{x}{x+1.5}=\frac{y}{y+1.2}=\frac{1.2}{1.8}

\frac{x}{x+1.5}=\frac{1.2}{1.8}

\frac{x}{x+1.5}=\frac{2}{3}

3x=2x+3

x=3

The length of BK is 3 m.

\frac{y}{y+1.2}=\frac{1.2}{1.8}

\frac{y}{y+1.2}=\frac{2}{3}

3y=2y+2.4

y=2.4

The length of CK is 2.4 m.

5 0
3 years ago
Read 2 more answers
A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 96m long and 74m wide.
Oduvanchick [21]

Answer:

11402.66 m^{2}

Step-by-step explanation:

The width of rectangle is the diameter of the semi-circle part

Area of one semicircle is given by \frac {0.5\pi d^{2}}{4}

Total area of semi circle will be 2\times\frac {0.5\pi d^{2}}{4}

Substituting 74 m for d and \pi as 3.14 we obtain

Total area semi-circle=2\times\frac {0.5*3.14\times 74^{2}}{4}=4298.66 m^{2}

Area of rectangle is given by the product of length and width

Rectangular area=96 m*74 m=7104 m^{2}

Total area of rectangular and semi-circles will be

4298.66 m^{2}+7104 m^{2}=11402.66 m^{2}

Therefore, area of training field is 11402.66 m^{2}

6 0
3 years ago
¿Cuál es la suma de los ángulos 1 al 6 en este paralelogramo?
Sveta_85 [38]

Answer:

Un paralelogramo es una forma plana con lados opuestos paralelos y de igual longitud.

Step-by-step explanation:

Los ángulos "a" y "b" suman 180 °, por lo que son ángulos suplementarios. NOTA: ¡Los cuadrados, rectángulos y rombos son todos paralelogramos

Espero que esto te ayude :)

4 0
3 years ago
How do i solve this?
vovikov84 [41]

Answer:

x = 4

y = 9

Step-by-step explanation:

It is given that figure (NPQR) is a square. One property of a square is that all sides of a square are congruent. This property also applies to the given square, thus one can make the following statement;

PQ = NR

Substitute,

10y - 29 = 5y + 16

Inverse operations,

10y - 29 = 5y + 16

-5y           -5y

5y - 29 = 16

    +29   +29

5y = 45

/5     /5

y = 9

Another property of a square is that all of the interior angles of a square have a measure of (90) degrees. Moreover, the diagonals (segment connect non-adjacent vertices) bisect these angles. Thus, twice the measure of an angle formed between a side and a diagonal forms a (90) degree angle. Therefore, one can draw the following conclusion;

2(m<QPR) = 90

Substitute,

2(6x + 21) = 90

Simplify,

12x + 42 = 90

Inverse operations,

12x + 42 = 90

        -42  -42

12x = 48

/12     /12

x = 4

4 0
3 years ago
Evaluate the expression when <br><br> a = -4 and c=5.<br><br> 6c-a
igomit [66]
=26
Explanation: 6 x 5 (c) = 30 30 - 4 (a) =26
Hope that helps :)
8 0
3 years ago
Read 2 more answers
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