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marshall27 [118]
3 years ago
14

When you sneeze, air is forcefully exhaled from your nose. As the air exits the nose, what is the last structure the air will pa

ss through?
Biology
1 answer:
inn [45]3 years ago
5 0

The last structure the air will pass through will be External nares

<u>Explanation:</u>

The upper portion of the respiratory tract is the nasal cavity and the nose. The external nose forms the first and foremost respiratory tract area. Nose is the major part that is responsible in exchanging air with the atmosphere. It is responsible for the human survival.

There are two openings in a nose. These are called as nostrils. They are also called as exterior nares. The air from the atmosphere when inhaled it enters into the nostril. from there is is sent to the nasal cavity. Nasal cavity is the place where the air that is inhaled will be purified and it is transported to various human parts. thus, when air contains any dust or impurities it will make you to sneeze thereby the air gets out of the nose through  External nares

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How many chromosomes would you expect to be in the daughter cells of the mosquito after meiosis? When starting with 6​
Mrac [35]

Answer:

The correct answer would be - three chromosomes.

Explanation:

Meiosis is the type of cell division that takes place in only sex cells and called reduction division as a single parent cell divide into four daughter cell that contains a half number of chromosomes as the parent cell.

The daughter cells are always haploid and have the half number of chromosomes. If an organism has 2n number of in its parent sex cell the daughter cells after meiosis will have n number of chromosomes

Therefore, mosquito = 2n = 6

after meiosis = n = 6/2 = 3

Thus, the correct answer would be - 3 chromosomes.

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In a population of tree frogs, the allele that causes yellow eyes (Y) is dominant over the allele that causes orange eyes (y). I
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Hardy-Weinberg Principle

Genotype frequency equation

 p^{2} +2pq +  q^{2} = 1

Where p² is the freq of homo dominant genotype, 2pq is the freq of heterozygous genotype and q² is the freq of homo recessive genotype.

Allele frequency equation

p + q = 1

Where p is the frequency of dominant alleles and q is the frequency of recessive alleles.

Yellow eyes in the frog offspring is a phenotype (physical trait) that would be a expressed by a geneotype (YY or Yy). This frequency, 0.85 includes: p² + 2pq

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q² = 0.15

p = \sqrt{0.15} 

Then p + \sqrt{0.15}  = 1

1 - \sqrt{0.15} = p

p = 0.613

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3 years ago
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