Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.
<h3>How do we verify if a sequence converges of diverges?</h3>
Suppose an infinity sequence defined by:

Then we have to calculate the following limit:

If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.
In this problem, the function that defines the sequence is:

Hence the limit is:

Hence, the infinite sequence converges, as the limit does not go to infinity.
More can be learned about convergent sequences at brainly.com/question/6635869
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Answer:
Step-by-step explanation:
<u>Given:</u>
- G = (11,-5)
- M = (4,-4)
- R = ?
<u>Solution</u>
<u>As per midpoint formula;</u>
- 4 = (11 + x)/2 ⇒ x + 11 = 8 ⇒ x = 3
- -4 = (-5 + y)/2 ⇒ y - 5 = -8 ⇒ y = -3
- R = (3, -3)
Answer:
A
Step-by-step explanation:
A good trick for trigonometric functions is to remember SOHCAHTOA:
Sin=<u>O</u>pposite over <u>H</u>ypotenuse
Cos=<u>A</u>djacent over <u>H</u>ypotenuse
Tan=<u>O</u>pposite over <u>A</u>djacent
The red arrows on the attachment indicate where opposite, hypotenuse, and adjacent are for angle A.
So in this case, the sin of angle A (opposite over hypotenuse) would be
and cos A (adjacent over hypotenuse) would be
.
I hope this helps!
Answer:
20% of the garden is in chillies.
Step-by-step explanation:
