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ladessa [460]
3 years ago
12

mason owns A trucking company. For every truck that goes out, Mason must pay the driver $13 per hour of driving and also has an

expense of one dollar per mile driven for gas and maintenance. On one particular day, the driver drove an average of 30 mph and masons total expenses for the driver, gas in truck maintenance were $258. write a system of equations that could be used to determine the number of hours to drive a word and the number of miles the truck drove. Define the variables that you used to write the system.
Mathematics
1 answer:
emmasim [6.3K]3 years ago
4 0

Answer:

Step-by-step explanation:

13h+1m=258

30m=h

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Answer:

correct option is A. $46840.50

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given data

taxable income = $209,150

solution

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Step-by-step explanation:

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You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte
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Answer:

a) P(x<5)=0.

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P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3

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P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6

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Therefore, the probability is P=1.

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