How to factor 25v^2+5v^2+30v+6 (please show work)

Mathematics

1 answer:

Makovka662 [10]2 years ago

3 0

So you have:

25v² + 5v² + 30v + 6

First you combine the like terms (all of the v²)

25v² + 5v² + 30v + 6

= 30v² + 30v + 6 <em>(25v² + 5v² = 30v²)</em>

Now notice that the largest common factor of all those numbers is 6. So you can take out a factor of 6:

30v² + 30v + 6

= 6 (5v² + 5v + 1)

----------------------------------------------------------

Answer:

25v² + 5v² + 30v + 6

= 30v² + 30v + 6

= 6 (5v² + 5v + 1)

You might be interested in

Find GCF of -50m ^4 n ^7 and 40m ^2 n ^10

trapecia [35]

-50m^4 n^7 = 10m^2n^7(-5m^2)<span>
and
40m^2 n^10 = 10</span>m^2 n^7(4n^3)

Answer: GCF = 10m^2 n^7

5 0

2 years ago

When solving a quadratic equation by using the square root method, and the final step results in square-rooting a “perfect squar

Elena L [17]

Answer:

Step-by-step explanation:

we're asked to solve the equation two x squared plus three is equal to 75 so in this situation it looks like we might be able to isolate the x squared pretty simply because there's only one term that involves the next year it's only this x squared term so let's try to do that so let me just rewrite it we have two x squared plus three is equal to 75 I'm going to try to isolate this x squared ...

4 0

2 years ago

Find the equation of the line that contains the points P1(-4,8) and P2(-6,8)...

olga_2 [115]

The equation would just be x=8 since the x of both points is 8.

6 0

2 years ago

Need help with a math probelm gvie 5 star if do

arsen [322]

Answer:

28 $units^{3}$