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natka813 [3]
2 years ago
13

WHAT IS THE VAULE OF X??? Please help me :,(

Mathematics
2 answers:
aliina [53]2 years ago
7 0
10/6= 1.66666667
1.66666667x12=20
So the answer is 20
katen-ka-za [31]2 years ago
4 0

Answer:

Since rest of the lines are divided in a ratio of 3:5

so.....3/5=12/X

12*5/3=20

Hope it helps

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A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben
juin [17]

Answer:

The estimation for the proportion for this case is \hat p = 0.21

And we know that the 99% confidence interval is given by:

0.21 \pm 0.045

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The confidence interval would be given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=2.58

The estimation for the proportion for this case is \hat p = 0.21

And we know that the 99% confidence interval is given by:

0.21 \pm 0.045

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

5 0
3 years ago
what is the perimeter of triangle PQR vertices P(-2, 9), Q(7,-3), and R(-2, -3) in the coordinate plane?
kipiarov [429]
This is a diffficult question was there a chart
6 0
3 years ago
Find the indicated part for the similar triangles.
sattari [20]
EF=9 cm. Both triangles are the same.
5 0
3 years ago
Read 2 more answers
Solve for x: -2x - 3 > 97
DENIUS [597]
To solve for x, we need to get it on one side by itself, and then to make sure we are left with ONLY x, no coefficients or anything.
-2x -3 > 97.
Add 3 to both sides.
-2x > 100.
Divide both sides by -2 (remember to flip the inequality when dealing with negatives).
x < -50
I hope this helps!
6 0
3 years ago
Can someone please answer. There is a picture. There is only one question. Thank you so much
fomenos
<span>(x-h)^2 + (y-k)^2 = r^2
(h, k) = (-5, -1)
r = 5
</span><span>(x+5)^2 + (y+1)^2 = 5^2
</span><span>(x+5)^2 + (y+1)^2 = 25</span>
4 0
3 years ago
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