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vova2212 [387]
3 years ago
15

How many solutions does the nonlinear system of equations graphed below have?

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
8 0
The answer is Three - apex !!!
NeTakaya3 years ago
3 0

Answer:

Three solutions.

Step-by-step explanation:

In order to solve system of equations by graphical method, we graph the system of equations. The intersection point (s) of the two graph would give us the solution.

If the graph of the equations intersect at 2 points then there will be 2 solutions, if there are 4 intersection then there would be 4 solutions and so on.

For the given graph, we  can see that there are three intersection points.

Hence, there would be three solutions.

You might be interested in
According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e
slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that p = 0.09

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

So

P(X < 4) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225

P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827

P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082

P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982

Finally

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

6 0
3 years ago
Median of 5,4,6,3,4?
taurus [48]

Answer:

4

Step-by-step explanation:

3, 4, 4, 5, 6

7 0
2 years ago
Read 2 more answers
Solve each system by substitution method. <br> X=2y+11<br> 7x+2y=13
Andreyy89

Step-by-step explanation:

you need to substitute the x in (7x +2y=13) with (x=2y+11) to solve it

7 0
1 year ago
Read 2 more answers
What is the definition of supplementary angles.
never [62]

Answer: either of two angles whose sum is 180°.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Jaun's age, x, is 4 times his age 15 years ago
KIM [24]

The expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

<h3>How to rewrite the statement as an expression?</h3>

The mathematical statement is given as

Jaun's age, x, is 4 times his age 15 years ago

From the statement, we have:

x represent Juan's current age

This means that his age 15 years ago is

15 years ago = x - 15

4 times his age 15 years ago is

4 * 15 years ago = 4 * (x - 15)

The above equation is equivalent to his current age

So, we have

x = 4 * (x - 15)

Hence, the expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

Read more about expressions at

brainly.com/question/2972832

#SPJ1

7 0
1 year ago
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