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Yakvenalex [24]
2 years ago
12

A basket contains seven apples and four peaches. You randomly select a piece of fruit and then return it to the basket. Then you

randomly select another piece of fruit. Both pieces of fruit are apples
Mathematics
2 answers:
Wewaii [24]2 years ago
7 0

Step-by-step explanation:

Total fruits = 7+ 4 = 11

Probability of apples = 7/ 11

Nataly_w [17]2 years ago
7 0
I need the question.....
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Is 7/18 rational or irrational
kramer

Answer:Rational

Step-by-step explanation: It is rational because it is repeating but not random like pi.

4 0
3 years ago
A snail traveled 3 over 8, of an inch in 3 minutes. How many inches can the snail travel in 9 minutes? Express the answer as a d
Elanso [62]
So, first of all, let's convert the fraction \frac{3}{8} into a decimal, which would be 0.375 (3 divided by 8)

The snail travels this far in 3 minutes. To find out how far it travels in nine minutes, we have to find out how many times 3 goes into 9.

9 / 3 = 3

Now. we simply multiply our decimal by three in order to get our answer!

0.375 x 3 = 1.125 inches

The answer is 1.125 inches!
3 0
3 years ago
My question got deleted so I'll post these into two separate
Agata [3.3K]

Answer:

see below

Step-by-step explanation:

1 million

1,000,000 seconds * 1 hour/ 3600 seconds * 1 day/ 24 hours * 1 year / 365 days

.031709792 years

Rounding to 3 decimal places

.032 years

50 years * 365 days/ 1 year * 24 hours/ 1 day * 3600 second / 1 hour    

1577000000 seconds    

46 inches * 1 ft/ 12 inches *  1 mile/5280 ft

0.000726 miles

8 0
3 years ago
How do you write 220% as a fraction or mixed number in simplest form?
Kay [80]
220% is 2.20 in decimal form in fraction 2 1/5
7 0
3 years ago
Read 2 more answers
Suppose the horses in a large stable have a mean weight of 1467lbs, and a standard deviation of 93lbs. What is the probability t
krok68 [10]

Answer:

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 1467, \sigma = 93, n = 49, s = \frac{93}{\sqrt{49}} = 13.2857

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable?

This is the pvalue of Z when X = 1467 + 9 = 1476 subtracted by the pvalue of Z when X = 1467 - 9 = 1458.

X = 1476

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1476 - 1467}{13.2857}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 1458

Z = \frac{X - \mu}{s}

Z = \frac{1458 - 1467}{13.2857}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

5 0
3 years ago
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