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Dafna11 [192]
3 years ago
11

What is 10.3 rounded to the nearest tenth

Mathematics
2 answers:
cricket20 [7]3 years ago
6 0

Answer:

10.3 is already rounded to the nearest tenth.

Step-by-step explanation:

Where the 3 is is the tenths place.

nika2105 [10]3 years ago
5 0

Answer:

10.3

Step-by-step explanation:

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The first barn contained 3 times more hay than the second one. After 20 tons of hay were removed from the first barn and 20 tons
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The solution would be like this for this specific problem:

 

a + 20 = 5/7 (3a - 20) <span>
a + 20 = (15a - 100)/7 </span><span>
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8 0
3 years ago
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A U.S. Travel Data Center survey of 500 adults found that 195 said they would take more vacations this year than last year. Cons
Lelechka [254]

Using the z-distribution, it is found that the 95% confidence interval for the true proportion of adults who said that they will travel more this year is (0.347, 0.433).

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

195 out of 500 people said they would take more vacations this year than last year, hence:

n = 500, \pi = \frac{195}{500} = 0.39

95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.39 - 1.96\sqrt{\frac{0.39(0.61)}{500}} = 0.347

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.39 + 1.96\sqrt{\frac{0.39(0.61)}{500}} = 0.433

The 95% confidence interval for the true proportion of adults who said that they will travel more this year is (0.347, 0.433).

A similar problem is given at brainly.com/question/15850972

5 0
3 years ago
What is the slope of the line through (6,9) and (7, 1)?
Virty [35]

Answer:

-8

Step-by-step explanation:

(9-1)/(6-7) = 8/-1 = -8

8 0
3 years ago
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