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katrin [286]
3 years ago
8

a substance is tested in a lab it is found to maintain a unique shape and is a good conductor of electricity if is made up of el

ectron protons and neutrons what state of matter is the substance most likely to be ?
Chemistry
2 answers:
Elodia [21]3 years ago
5 0
B im just typing more because it has to be longer than 20 characters
zloy xaker [14]3 years ago
5 0

Explanation:

It is known that a solid substance will be made up of atoms which are strongly held together. And, each atom of this solid substance consists of protons, neutrons and electrons.

Only solid substances have a fixed shape and volume.

As electricity is the flow of electrons and a solid substance is able to conduct electricity if it has free electrons available.

For example, in solid state also copper is a good conductor of heat and electricity.

Thus, we can conclude that when a substance is tested in a lab it is found to maintain a unique shape and is a good conductor of electricity if is made up of electron protons and neutrons then state of matter most likely to be solid.

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How many atoms of San are in 0.796 moles of this element
xenn [34]

Answer:

4.8× 10²³ atoms

Explanation:

Given data:

Number of moles of San element = 0.796 mol

Number of atoms present = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

0.796 mol ×  6.022 × 10²³ atoms / 1mol

4.8× 10²³ atoms

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3 years ago
What is the pH of a solution of 0.800 M KH2PO4, potassium dihydrogen phosphate?
Nookie1986 [14]
KH₂PO₄ hydrolyzes as;
H₂PO₄⁻ + H₂O ↔ H₃PO₄ + OH⁻
Let x amount of H₂PO₄⁻ has reacted with water then,
Kb₁ = [H₃PO₄][OH⁻] / [H₂PO₄⁻]
[H₂PO₄⁻] = 0.8-x M
Kb₁ = x² / (0.8 - x)
Given Ka₁ = 7.5 x 10⁻³
so Kb₁ = 1 x 10⁻¹⁴ / (7.5 x 10⁻³) = 1.33 x 10⁻¹²
From this information:
1.33 x 10⁻¹² = x² / 0.8
x = [OH⁻] = 1.03 x 10⁻⁶ M
pOH = - log (1.03 x 10⁻⁶) = 5.99
pH = 14 - pOH = 14 - 5.99 = 8.01 



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