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Daniel [21]
1 year ago
6

you are running a transformation reaction, and in your microfuge tube currently is your plasmid and your insert fragments (both

containing compatible sticky ends). the other student worker who worked the previous lab shift, however, did not put the ligase back into the freezer, so it denatured and will no longer work, but you didn't know this at the time, and added it to your solution. explain exactly what will (or will not) happen now in your experiment, and how your transformation will be affected.
Chemistry
1 answer:
ElenaW [278]1 year ago
4 0

A foreign DNA molecule can be incorporated into a bacterial plasmid during a transformation reaction.

<h3>How to explain the reaction?</h3>

With the aid of two enzymes, ligase and restriction enzymes, a foreign DNA molecule can be incorporated into a bacterial plasmid during a transformation reaction. Each enzyme detects a target DNA sequence and cuts it nearby, while ligase aids in connecting the DNA. When two bits of DNA have complimentary bases, it facilitates their joining.

Plasmid and the insert fragment are both present in the microfuge tube, and they both have compatible sticky ends. However, the ligase has been denatured and is no longer active because the prior student left it outside rather than freezing it; despite this, we had already put the ligase into the tube. Ligase aids in binding the plasmid and insert fragments together, but because it is denatured in this instance, it will no longer be able to do so. As a result, no transformation process will take place. And since ligase links DNA fragments together by catalyzing the development of connections between the nearby nucleotides, the two fragments will not be able to unite.

Learn more about reactions on:

brainly.com/question/11231920

#SPJ1

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How many grams of Na2CO3 must be dissolved into 155g of water to create a solution with a molarity of 8.20 mol/kg
zhannawk [14.2K]

Answer:

135g Na2CO3

Explanation:

I'm going to assume you mean Molality which is mol solute/kg solvent

Molarity would be mol soute/ L solution

we know we have 155g of water which is .155 kg

essentially we have the equation:

mol/kg = 8.20

we substitute .155 in for kg and get:

mol/.155 = 8.20

Solving this  gives mol = 1.271

now we must convert to grams using the molar mass

Molar mass Na2CO3 = 106G/mol

so to cancel moles we multiply:

1.271mol x 106g/mol

= 135g

4 0
3 years ago
HELPPPPPPPPPP!!!!!!!!!!!!!!
SOVA2 [1]
The Answer is D cause of the people going back and forth.
4 0
3 years ago
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Outline the difference between compounds and mixtures. State two examples of each.
alekssr [168]

Compounds are elements and its a pure substance with a gised composition.

Mixtures two or more subtances mixed to together.There are 2 type of mixtures.

Homegenous Mixtures (Solutions)-Two or more substances mixed but is uniform, you cant see the different mixtures.

Ex:Sugar mixed with water.The sugar dissolves and becomes one with the water.

Heterogeneous Mixtures-Two or more substances mixed but is not uniformed.You can see all the substances put into the mixture.

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3 0
2 years ago
How many grams of Cabr2 would be needed to create 450 mL of a 2.00 M solution?
Yanka [14]

Answer:

Mass = 179.9 g

Explanation:

Given data:

Volume of solution = 450 mL

Molarity of solution = 2.00 M

Mass in gram required = ?

Solution:

Volume of solution = 450 mL× 1 L / 1000 mL = 0.45 L

Molarity = number of moles of solute/ Volume of solution in L

2.00 M = number of moles of solute / 0.45 L

Number of moles of solute = 2.00 M × 0.45 L

M = mol/L

number of moles of solute = 0.9 mol

Mass of CaBr₂ in gram:

Mass = number of moles ×  molar  mass

Mass = 0.9 mol ×199.89 g/mol

Mass = 179.9 g

6 0
3 years ago
What is the mass in grams of a single formula unit of silver chloride, AgCI? A) 4.21 x 1021 g B) 8.61 x 10258 C) 1.66 x 10-248 D
bekas [8.4K]

Answer: D) 2.38*10^-^2^2 g

Explanation: The question asks to convert formula unit to grams. It is a unit conversion problem.

1 mole equals to Avogadro number of formula units. So, to convert the given number of formula units to moles, we need to divide by the Avogadro number. After this, we do moles to grams conversion and for this the moles are multiplied by the molar mass of the compound. Molar mass of AgCl is 143.32 gram per mol.

1FormulaUnitAgCl(\frac{1mol}{6.022*10^2^3formulaUnits})(\frac{143.32g}{1mol})

= 2.38*10^-^2^2 g

So, the correct option is D) 2.38*10^-^2^2 g

7 0
3 years ago
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