Which statement best explains how the solution should be made? Add 49. 6 mL of 0. 250 M sucrose to 400. 0 mL of water to get 400
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Answer:
The number of sulfur atoms in 1 g of sulfur is:- atoms
Explanation:
Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by .
Avogadro constant:-
Given atomic mass of sulfur = 32 u
Which means that:-
32 g of sulfur contains of atoms
Also,
1 g of sulfur contains of atoms
<u>So, The number of sulfur atoms in 1 g of sulfur is:- atoms</u>
Taking into account the reaction stoichiometry, 102 grams of Al₂O₃ are formed when 48 grams of O₂ react.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
4 Al + 3 O₂ → 2 Al₂O₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Al: 4 moles
- O₂: 3 moles
- Al₂O₃: 2 moles
The molar mass of the compounds is:
- Al: 27 g/mole
- O₂: 32 g/mole
- Al₂O₃: 102 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- Al: 4 moles ×27 g/mole= 108 grams
- O₂: 3 moles ×32 g/mole= 96 grams
- Al₂O₃: 2 moles ×102 g/mole= 204 grams
The following rule of three can be applied: if by reaction stoichiometry 96 grams of O₂ form 204 grams of Al₂O₃, 48 grams of O₂ form how much mass of Al₂O₃?
<u><em>mass of Al₂O₃= 102 grams</em></u>
Finally, 102 grams of Al₂O₃ are formed when 48 grams of O₂ react.
Learn more about the reaction stoichiometry:
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The Lewis structure of Chloroacetate (H₂CClCO₂) is given below. In structure it is shown that carbon has a double bond with one oxygen atom and two single bonds with CH₂Cl and O⁻.
Formal Charge;
Formal charge is caculated as,
Formal charge = # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]
Formal charge on Oxygen (Highlighted Red);
Formal charge = 6 - [ 6 + 2/2]
Formal charge = 6 - [6 + 1]
Formal charge = 6 - [7]
Formal charge = -1
Formal Charge;
Formal charge is caculated as,
Formal charge = # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]
Formal charge on Oxygen (Highlighted Red);
Formal charge = 6 - [ 6 + 2/2]
Formal charge = 6 - [6 + 1]
Formal charge = 6 - [7]
Formal charge = -1