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snow_tiger [21]
3 years ago
10

Which statement best explains how the solution should be made? Add 49. 6 mL of 0. 250 M sucrose to 400. 0 mL of water to get 400

. 0 mL of 0. 0310 M sucrose. Add 49. 6 mL of 0. 0310 M sucrose to 350. 4 mL of water to get 400. 0 mL of 0. 250 M sucrose. Add 49. 6 mL of 0. 250 M sucrose to 350. 4 mL of water to get 400. 0 mL of 0. 0310 M sucrose.
Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
7 0
The Last one thank you thank you hope this helped!
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A 35.0 ml sample of 0.225 m hbr was titrated with 42.3 ml of koh. What is the concentration of the koh?
Lemur [1.5K]

Answer:

The concentration of KOH is 0.186 M

Explanation:

First things first, we need too write out the balanced equation between HBr and KOH.

This is given as;

KOH (aq) + HBr (aq) → KBr (aq) + H2O (l)

From the reaction above, we can tell that it takes 1 mole of KOH to react with 1 mole of HBr.

We use the acid base formular in calculating unknown concentrations. This is given as;

\frac{CaVa}{CbVb}  = \frac{na}{nb}

where;

Ca = Concentration of acid

Va = Volume of acid

Cb = Concentration of base

Vb = Volume of base

na = Number of moles of acid

nb = Number of moles of base

KOH is the base and HBr is acid.

Hence;

Ca = 0.225

Va = 35

Cb = ?

Vb = 42.3

na = 1

nb = 1

Making Cb subject of formular we have;

Cb = \frac{CaVaNb}{VbNa}

Cb = (0.225 * 35 * 1) / (42.3 * 1)

Cb = 0.186 M

5 0
3 years ago
If the same materials are used to build a voltaic cell and an electrolytic cell, how would the chemical reactions compare?
nadya68 [22]
In the electrolytic cell, depending on the polarity of the battery, either a more vigorous reaction (though the same as the voltaic cell) would occur, or the reverse would.
3 0
3 years ago
What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?
mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

C=\frac{n}{V} .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is K_{2}SO_{4} thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass

Putting the values,

n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol

Thus, number of moles of  K_{2}SO_{4} will be 0.1061\times 0.5=0.053 mol.

The volume of solution is 225 mL, converting this into L,

1 mL=10^{-3}L

Thus,

225 mL=0.225 L

Putting the values in equation (1),

C=\frac{(0.053 mol}{0.225 L}=0.236 M

Therefore, concentration of potassium sulfate solution is 0.236 M.


4 0
3 years ago
Attached are two chemistry questions I need help with. thank you to whoever helps me out
ivann1987 [24]
13.6 
a) yes Pb is more reactive  that Ag, Pb before Ag
b) no, Cu after H
c) yes, Cl2 is more active than I2
4) yes, Mg is more active

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Al ³⁺  more active than Zn²⁺, Mn can react with  Zn²⁺, but not with Al ³⁺ , because Mn after Al but before Zn
4 0
3 years ago
Type of Reaction<br> _Mg₃N2 →
nevsk [136]
Ionic reaction when a metal and non metal are together a molecule is when a metal abs metal react hope this helps
8 0
3 years ago
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