The question is incomplete, the complete question is;
1. Given: 2A(g) <-> 2B(g) + C(g). At a particular temperature, K = 1.6x104.
At a higher temperature, K = 1.8x10-5. Placing the equilibrium mixture in an ice bath (thus lowering the temperature) will...
cause [A] to increase
cause [B] to increase
gave no effect
cannot be determined
Answer:
cause [B] to increase
Explanation:
We have to have it behind our minds that; for an exothermic reaction, when the temperature is increased, the value of the equilibrium constant decreases. On the other hand, for an endothermic reaction, increasing the temperature increases the value of the equilibrium constant.
In this particular case, increasing the temperature decreased the equilibrium constant from K = 1.6x104 to K = 1.8x10-5 meaning that the equilibrium constant decreased with increase in temperature. This means that the reaction is exothermic and a decrease in temperature will favour the forward reaction hence more B is produced.
Answer:
Explanation:
Hello there!
in this case, according to the given information, it turns out firstly necessary for us to write up the chemical equation as shown below:
Thus, we calculate the mass of BaCl2 stoichiometrically related to the produced 1.658 g of precipitate in order to discard it from the sample:
Thus, the mass percentage is calculated as shown below:
Regards!
Because room temperature is below the ignition temperature of petrol. At this temperature energy in the form of heat, flame, or electric spark is needed to start the reaction.
[Kr]4d3
The configuration of Nb2+ is [Kr]4d3. Nb2+ also has an odd number of valence electrons.
Answer:
The three statements are true
Explanation:
For the reaction:
I₂O₅(s) + 5CO(g) → I₂(s) + 5CO₂(g)
State oxidation of iodine in I₂O₅ is:
5 O²⁻ = 10⁻
As you have 2 I and the molecule has no charge, <em>oxidation state of I is +5</em>.
The carbon in CO has an oxidation state of +2 and in CO₂ is +4. That means <em>the carbon is oxidized</em>
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An oxidizing agent is a substance that produce the oxidation of the agent that reacts with this one. CO is oxidized because of I₂O₅ is producing its oxidation being <em>the oxidizing agent</em>
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Thus,<em> the three statements are true</em>.
