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Tom [10]
3 years ago
11

Any has math they need help with??

Mathematics
1 answer:
Kobotan [32]3 years ago
5 0
Factor x^2+1 over Z2[x], just to give you something to do.
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Find the approximate area of the shaded region, below consisting of a square with a circle cut out of it. use 3.14
artcher [175]

Answer:sorry

Step-by-step explanation:there is no attachment

4 0
3 years ago
HELP IM DOING THE TEST
enyata [817]

Answer:

The slope of the line that contains the points (-1, 2) and (4, 3) is:

  • Slope = m =  1 / 5        

Step-by-step explanation:

Given the points

  • (-1, 2)
  • (4, 3)

Finding the slope between (-1, 2) and (4, 3)

\left(x_1,\:y_1\right)=\left(-1,\:2\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

               =  [3 - 2] / [4 - (-1)]

               = 1 / 5                  

Thus, the slope of the line that contains the points (-1, 2) and (4, 3) is:

  • Slope = m =  1 / 5            
3 0
3 years ago
The ratio of 1 hour to 300 seconds is:<br> (i) 1:12;<br> (i) 12:1; (iii) 1 : 5;<br> (iv) 5:1
DaniilM [7]

Answer:

1:12

Step-by-step explanation:

I hope this helps!

7 0
3 years ago
Convert 3x-4y = 9 to slope intercept form. What are the slope and y - intercept ?
Alecsey [184]

Answer:

Slope intercept form; -4y = -3x + 9

Y-intercept; 9

3 0
3 years ago
Read 2 more answers
A researcher was interested in comparing the resting pulse rates of people who exercise regularly and people who do not exercise
DiKsa [7]

Answer:

We Reject H₀ if t calculated > t tabulated

But in this case,

0.83 is not greater than 2.056

Therefore, we failed to reject H₀

There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.

Step-by-step explanation:

Refer to the attached data.

The Null and Alternate hypothesis is given by

Null hypotheses = H₀: μ₁ = μ₂

Alternate hypotheses = H₁: μ₁ ≠ μ₂

The test statistic is given by

$ t = \frac{\bar{x}_1  - \bar{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }  $

Where \bar{x}_1 is the sample mean of people who do not exercise regularly.

Where \bar{x}_2 is the sample mean of people who do exercise regularly.

Where s_1 is the sample standard deviation of people who do not exercise regularly.

Where s_2 is the sample standard deviation of people who do exercise regularly.

Where n_1 is the sample size of people who do not exercise regularly.

Where n_2 is the sample size of people who do exercise regularly.

$ t = \frac{72.7  - 69.7}{\sqrt{\frac{10.9^2}{16} + \frac{8.2^2}{12} } }  $

t = 0.83

The given level of significance is

1 - 0.95 = 0.05

The degree of freedom is

df = 16 + 12 - 2 = 26

From the t-table, df = 26 and significance level 0.05,

t = 2.056 (two-tailed)

Conclusion:

We Reject H₀ if t calculated > t tabulated

But in this case,

0.83 is not greater than 2.056

Therefore, We failed to reject H₀

There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.

4 0
3 years ago
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