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harina [27]
4 years ago
8

If a material contains three elements but not joined in a fixed proportion, it is a(an) A. mixture. B. compound. C. atom. D. non

e of the above
Chemistry
2 answers:
BartSMP [9]4 years ago
7 0
 B. compound a material that contains three elements joined in a fixed proportion
denis-greek [22]4 years ago
4 0
The correct answer will be b
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PLEASE HELP----
balandron [24]
Actual yield of Fe2(So4)3 = 18.5g

2FePo4 + 3Na2SO4 -> Fe2(SO4)3 + 2Na3PO4

Mole of FePO4 = mass of it / its molar mass =
25 g / (55.8 + 31 + 16*4) = 0.166 mol

every 2 mole of FePO4 will form 1 mole of Fe2(SO4)3

Mole of Fe2(SO4)3 produced = 0.166 / 2 = 0.0829 mol

0.0829 * (55.8*2 + 3*(32.1+ 16*4)) = 33.148 g of Fe2(SO4)3

18.5 / 33.148 * 100 = 55.8%

3 0
3 years ago
The element with the most stable nucleus and smallest mass per particle is
Margaret [11]
"18) the element with the most stable nucleus and smallest mass per particle is:A) uranium.B)argon C) helium."
4 0
4 years ago
calculatorn the past, many students have listed that the accidental addition of too much acetic acid contributed greatly to the
Tresset [83]
Is that supposed to be a paragraph
6 0
4 years ago
g An analytical chemist is titrating of a solution of diethylamine with a solution of . The of diethylamine is . Calculate the p
Serga [27]

Answer:

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Explanation:

5 0
3 years ago
The vapor pressure of ethanol is 54.68 mm Hg at 25°C. How many grams of estrogen (estradiol), C18H24O2, a nonvolatile, nonelectr
amm1812

Answer:

30.5 g of estrogen

Explanation:

Lowering vapor pressure formula → P° - P' = P° . Xm

P° → Vapor pressure of pure solvent → 54.68 mmHg

P' → Vapor pressure of solution → 53.46 mmHg

54.68 mmHg - 53.46 mmHg = 54.68 mmHg . Xm

0.0223 = Xm → This is the mole fraction for solute

Moles of solute / Total moles

Total moles = Moles of solute + Moles of solvent

Let's determine the moles of solvent → 228 g / 46.07 g/mol = 4.95 moles

Let's determine the moles of solute

Moles of solute / Moles of solute + 4.95 = 0.0223

Moles of solute = 0.0223 . Moles of solute + 0.110

0.9777 moles of solute = 0.110

Moles of solute = 0.110 / 0.9777 → 0.112

Now we can convert the moles to mass to finish the excersise:

0.112 mol . 272.4 g/mol = 30.5 g

3 0
3 years ago
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