A 50.0 g gold spoon at 10.0 °c is placed in a cup of how water 95.0 °c. how much heat does the water lose to the spoon if the sp
oon reaches a temperature of 59.0 °c?
2 answers:
The water lost 313.6 J of heat to the spoon
<h3>Further explanation </h3>Temperature is one of the principal quantities that shows the degree of heat or cold from an object / space
Temperature is used as a guide to the level of heat energy from objects
Temperature cannot be measured by the surface of the hand because it is not accurate but can be measured by a thermometer. Temperature units include Celsius, Fahrenheit, Reamur or Kelvin
Whereas heat is a form of energy that can flow from high-temperature objects to low-temperature objects.
So heat moves when there is a difference in temperature and can increase or decrease the temperature. An object that receives a lot of heat will cause a large increase in temperature
The amount of heat is influenced by the mass of the object and the difference in temperature
Can be formulated
Q = m.c.ΔT
Q: heat received or removed by an object (J)
m: object mass (kg)
c: heat type substance (J / kg⁰C)
ΔT: temperature change (⁰C)
When A 50.0 g of gold spoon at 10.0 ° c is placed in a cup of hot water 95.0 ° c. Heat balance occurs:
q lost = q gain
q lost from water = q gain from spoon
q lost from water = m. cp (gold). delta t
The specific heat of gold is 0.128 J / g ° C.
q lost from water = 50 g. 0.128. (59-10)
q lost from water = 313.6 J
<h3>Learn more </h3>
heat and temperature
grams of water
decrease heat transfer between two objects
Keywords: heat gain, heat lost
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Answer:
1.181 × 10²⁴ molecules CO₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
86.34 g CO₂
<u>Step 2: Identify Conversion</u>
Avogadro's Number
Molar Mass of C - 12.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol
<u>Step 3: Convert</u>
<u /> = 1.18141 × 10²⁴ molecules CO₂
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂