Carbohydrates. CH2O is the most basic formula of simple sugars.Empirical formula is the lowest whole number ratio of atoms in a formula.For example glucose is C6H12O6 can be reduced by 6 to get CH2O. Simples sugars include glucose and fructose which can serve as sources of energy for fats and amino acids.
Answer: There are 
molecules in 6.73 moles of phosphorus trichloride
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
1 mole of 
contains = molecules
Thus 6.73 moles of contains = 
molecules
Thus there are molecules in 6.73 moles of phosphorus trichloride
Answer:
2H₂O₂ → 2H₂O + O₂
24.7 L are the liters of formed oxygen.
Explanation:
We state the reaction:
2H₂O₂ → 2H₂O + O₂
2 moles of peroxide decompose to 2 moles of water and 1 mol of oxygen gas.
We convert the mass to moles: 75 g . 1 mol / 34 g = 2.20 moles
As ratio is 2:1, per 2.20 moles of peroxide I would produce the half of moles, of O₂ → 2.20 /2 = 1.10 moles
We convert the moles to mass → 1.10 mol . 32 g / 1 mol = 35.3 g
Let's use oxygen's density to find out the volume
δ O₂ = 1.429 g/L (mass/volume)
35.3 g . 1L / 1.429g = 24.7 L
<h3>
Answer:</h3>
Al₂(SO₄)₃
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Explanation:</h3>
We are given percentage composition of elements in a compound;
- Aluminium is 15.77%
- Sulfur is 28.11 %
- Oxygen is 56.12%
We are required to calculate the empirical formula of the compound.
- Assuming the mass of the compound is 100 g then the masses of the elements is;
Aluminium = 15.77 g
Sulfur = 28.11
Oxygen = 56.12
We can determine the number of moles of each;
Moles of Aluminium = 15.77 g ÷ 26.98 g/mol
= 0.585 moles
Moles of sulfur = 28.11 g ÷ 32.07 g/mol
= 0.877 moles
Moles of Oxygen = 56.12 g ÷ 16.0 g/mol
= 3.5075 moles
- But, the empirical formula is the simplest whole number ratio of elements in a compound.
- Therefore; we need to get the ratio of moles of the above elements;
Aluminium : Sulfur : Oxygen
0.585 mol : 0.877 mol : 3.5075 mol
0.585/0.585 : 0.877/0.585 : 3.5075/0.585
1 : 1.5 : 6
But, we need whole number ratios, therefore;
= (1 : 1.5 : 6 ) × 2
= 2 : 3 : 12
Therefore; the formula of the compound is Al₂S₃O₁₂
The compound is written as Al₂(SO₄)₃
Thus, the empirical formula of the compound is Al₂(SO₄)₃
