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Serhud [2]
3 years ago
9

Identify each enthalpy change by name and classify each change as exothermic or endothermic.

Chemistry
2 answers:
PtichkaEL [24]3 years ago
7 0

Answer:

1. C)

2. B)

3. D)

4. A)

Explanation:

Enthalpy change is the heat of the reaction measured at constant pressure.

i.e. q_{p}=\Delta H

Chemical reactions are accompanied either by the absorption of heat (endothermic) or by the release of heat (exothermic)

1) 1 mol NaCl (s) ↔ 1 mol NaCl(l)

Ans: C) Molar heat of fusion; endothermic

Molar heat or enthalpy of fusion is the amount of energy absorbed when a solid melts into a liquid. It is an endothermic process since heat is absorbed.

2. C4H10 O(l) ↔ C4H10O (g)

Ans: B) Molar heat of vaporization; endothermic

Molar heat or enthalpy of vaporization is the amount of energy absorbed when a liquid evaporates into a gas. It is an endothermic process since heat is absorbed.

3. H2O(g) ↔ H2O (l)

Ans: D Molar heat of condensation; exothermic

Molar heat or enthalpy of condensation is the amount of energy released when a gas condenses into a liquid. It is an exothermic process since heat is released.

4. 1 mol NaCl(s) + 3.88 kJ/mol ↔ 1 mol NaCl(aq)

Ans: A) Molar heat of solution; endothermic

Heat of solution is the amount of heat absorbed when 1 mole of a substance is dissolved in water.

Len [333]3 years ago
3 0
We classify them as follows:

1. 1 mol NaCl (s) à 1 mol NaCl(l) 
C Molar heat of fusion; endothermic

2. C4H10 O(l) à C4H10O (g) 
B Molar heat of vaporization; endothermic

3. H2O(g) à H2O (l) 
D Molar heat of condensation; exothermic

4. 1 mol NaCl(s) + 3.88 kJ/molà 1 mol NaCl(aq) 
A Molar heat of solution; endothermic
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I need help with 1,2,3, and 4
Schach [20]

Answer:

  • Problem 1: 1.85atm
  • Problem 2: 110mL
  • Problem 3: 290 mL
  • Problem 4: 1.14 atm

Explanation:

Problem 1

<u>1. Data</u>

<u />

a) P₁ = 3.25atm

b) V₁ = 755mL

c) P₂ = ?

d) V₂ = 1325 mL

r) T = 65ºC

<u>2. Formula</u>

Since the temeperature is constant you can use Boyle's law for idial gases:

          PV=constant\\\\P_1V_1=P_2V_2

<u>3. Solution</u>

Solve, substitute and compute:

         P_1V_1=P_2V_2\\\\P_2=P_1V_1/V_2

        P_2=3.25atm\times755mL/1325mL=1.85atm

Problem 2

<u>1. Data</u>

<u />

a) V₁ = 125 mL

b) P₁ = 548mmHg

c) P₁ = 625mmHg

d) V₂ = ?

<u>2. Formula</u>

You assume that the temperature does not change, and then can use Boyl'es law again.

          P_1V_1=P_2V_2

<u>3. Solution</u>

This time, solve for V₂:

           P_1V_1=P_2V_2\\\\V_2=P_1V_1/P_2

Substitute and compute:

        V_2=548mmHg\times 125mL/625mmHg=109.6mL

You must round to 3 significant figures:

        V_2=110mL

Problem 3

<u>1. Data</u>

<u />

a) V₁ = 285mL

b) T₁ = 25ºC

c) V₂ = ?

d) T₂ = 35ºC

<u>2. Formula</u>

At constant pressure, Charle's law states that volume and temperature are inversely related:

         V/T=constant\\\\\\\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

The temperatures must be in absolute scale.

<u />

<u>3. Solution</u>

a) Convert the temperatures to kelvins:

  • T₁ = 25 + 273.15K = 298.15K

  • T₂ = 35 + 273.15K = 308.15K

b) Substitute in the formula, solve for V₂, and compute:

        \dfrac{V_1}{T_1`}=\dfrac{V_2}{T_2}\\\\\\\\\dfrac{285mL}{298.15K}=\dfrac{V_2}{308.15K}\\\\\\V_2=308.15K\times285mL/298.15K=294.6ml

You must round to two significant figures: 290 ml

Problem 4

<u>1. Data</u>

<u />

a) P = 865mmHg

b) Convert to atm

<u>2. Formula</u>

You must use a conversion factor.

  • 1 atm = 760 mmHg

Divide both sides by 760 mmHg

       \dfrac{1atm}{760mmHg}=\dfrac{760mmHg}{760mmHg}\\\\\\1=\dfrac{1atm}{760mmHg}

<u />

<u>3. Solution</u>

Multiply 865 mmHg by the conversion factor:

    865mmHg\times \dfrac{1atm}{760mmHg}=1.14atm\leftarrow answer

3 0
3 years ago
(Please help will mark brainliest!)
arsen [322]

We know that Weighted atomic mass of Element is Calculated based upon their existence of isotopes and the Relative abundance of these isotopes.

Given that the Element X is Composed of :

Isotope                       Relative abundance                   Atomic Mass

⁵⁵X                                        70%                                               55

⁵⁶X                                        20%                                               56

⁵⁷X                                        10%                                                57

Weighted Atomic Mass of Element X :

= (0.70)(55) + (0.20)(56) + (0.10)(57)

= 38.50 + 11.2 + 5.70

= 55.4

So, the Weighted Atomic Mass of Element X is 55.4

6 0
3 years ago
Which statement applies to transverse waves?
11Alexandr11 [23.1K]

Answer:

the waves have a trough

Explanation:

just took the test on edg.

6 0
3 years ago
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Define Saturated Solution. What happens as a saturates solution cools?
solong [7]

Saturated solution is a solution in which no more solute can be dissolved in the solvent. When saturated solution cools, the solution began precipitate from the solution, because under lower temperature, usually, less amount solute can be dissolved in the solvent.

8 0
3 years ago
Read 2 more answers
Uranium (VIII) Sulfide formula
tresset_1 [31]

Answer:

US₂

Explanation:

Uranium sulfide (US₂)

Uranium atomic symbol = U

Sulfur atomic symbol = S

Uranium valency = +4

Sulfur valency = -2

So;

Uranium sulfide (US₂)

8 0
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