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gladu [14]
3 years ago
11

How many moles of sodium acetate (nach3coo) must be added to 1.000 liter of a 0.500 m solution of acetic acid (ch3cooh) to produ

ce a ph of 5.061? the ionization constant of acetic acid is 1.8 Ã 10â5 . answer in units of mol?
Chemistry
1 answer:
Alenkinab [10]3 years ago
4 0
When PH = -㏒[H3O+] 
and we have PH = 5.061 
by substitution:
∴ [ H3O+] = 10^-5.061 = 8.7x10^-6
when we have Ka = [CH3COO-][H3O+] / [CH3COOH]
we have Ka = 1.8x10^-5 & [H3O+] = 8.7x10^-6m & [CH3COOH] = 0.5 m 
by substitution in Ka formula:
1.8x10^-5 = [CH3COO-]*(8.7x10^-6) / 0.5
∴[CH3COO-] = 1.034
∴we need  to add 1.034 mol of sodium acetate
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How many moles of KClO3 reacted if 9 moles of O2 were produced in this reaction: 2KClO3 → 2KCl + 3O2
kherson [118]
2 mol KClO₃ - 3 mol O₂
x mol KClO₃ - 9 mol O₂

x=9*2/3= 6 mol
3 0
3 years ago
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Ira Lisetskai [31]
Potassium it is the answer

6 0
3 years ago
A chemical plant produces ammonia using the following reaction at a very high temperature and pressure. Which design issue is mo
Lorico [155]

Answer:

D. The equipment needed to accommodate the high temperature and pressure will be expensive to produce.​

Explanation:

Hello!

In this case, for the considered reaction, it is clear it is an exothermic reaction because it produces energy; and therefore, the higher the temperature the more reactants are yielded as the reverse reaction is favored. Moreover, since the effect of pressure is verified as favoring the side with fewer moles; in this case the products side (2 moles of ammonia).

In such a way, the high pressure favors the formation of ammonia whereas the high temperature the formation of hydrogen and nitrogen and therefore, option A is ruled out. Since the high pressure shifts the reaction rightwards and the high temperature leftwards, we would not be able to know whether the reaction has ended or not because it will be a "go and come back" process, that is why B is also discarded. Now, since hydrogen and nitrogen would be the "wastes", we discard C because they are not toxic. That is why the most accurate answer would be D. because it is actually true that such equipment is quite expensive.

Best regards!

6 0
2 years ago
When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°
dlinn [17]

Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.30^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant =  

m= molality = \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579

8.30^0C=1\times K_f\times 0.579

K_f=14.3^0C/m

Let Mass of solute (KBr) = x g

8.3^0C=1.72\times 14.3\times \frac{xg\times 1000}{119g/mol\times 1450g}

x=58.2g

Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

7 0
2 years ago
B.Use the words inside the box to complete the chart below​
Dennis_Churaev [7]

Answer:

Answered below

Explanation:

>> ice is solid

>> water is liquid

>> Steam is gas

>> Ice → water = melting

>> water → steam = evaporation

>> steam → water = condensation

>> water → ice = freezing

7 0
3 years ago
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