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mezya [45]
3 years ago
9

5

#10;" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Jlenok [28]3 years ago
8 0
<span>5^2 x = 625
25x = 625
    x = 625 / 25
    x = 25</span>
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Race car driver Mario won 3 races and earn 75 points for each win. During the fourth race, he had dedications of 55 points, 104
svet-max [94.6K]

Answer:

he has 472 points now.

Step-by-step explanation:

5 0
3 years ago
Determine whether the graphs of y=-7x-4 and -y=7x+4 are parallel, perpendicular, coincident or none of these
horsena [70]

we are given

y=-7x-4

-y=7x+4

we can multiply -1 on both sides of second equation

-1*-y=-1(7x+4)

y=-7x-4

we can see that

both equations becomes same

so, they are coincident............Answer

5 0
3 years ago
Read 2 more answers
John joined a gym for 6 months. He pays 20$ per month plus a membership fee. If his bill is 150$, what was the membership fee?
Jlenok [28]

Answer:

Step-by-step explanation:

If he's been at the gym for 6 months, and he is charged $20 each month, then he has paid $120 dollars, not counting his membership fee. His total bill is $150.

150-120= $30

His membership fee was $30.

Hope this helps!

Mark Brainliest plz!

3 0
3 years ago
Read 2 more answers
What are the roots of the equation 9x^2 + 54x +82 = 0 in simplest a + bi form?​
s344n2d4d5 [400]

Answer:

The roots are

<h3>x =  - 3 +  \frac{1}{3}  i \:  \:  \: or \:  \:  \: x =  - 3 -  \frac{1}{3} i \\</h3>

Step-by-step explanation:

9x² + 54x + 82 = 0

Using the quadratic formula

That's

<h3>x =  \frac{ - b\pm \sqrt{ {b}^{2}  - 4ac} }{2a}</h3>

From the question

a = 9 , b = 54 , c = 82

Substitute the values into the above formula and solve

That's

<h3>x =  \frac{ - 54\pm \sqrt{ {54}^{2}  - 4(9)(82)} }{2(9)}  \\ x =  \frac{ - 54\pm \sqrt{2916 - 2952} }{18}  \\ x =  \frac{ - 54\pm \sqrt{ - 36} }{18}  \\ x =  \frac{ - 54\pm 6i}{18}</h3>

Separate the real and imaginary parts

That's

<h3>x =  -  \frac{54}{18} \pm \frac{6}{18}  \: i \\ x =  - 3\pm \frac{1}{3} i</h3>

We have the final answer as

<h3>x =  - 3 +  \frac{1}{3}  i \:  \:  \: or \:  \:  \: x =  - 3 -  \frac{1}{3} i \\</h3>

Hope this helps you

5 0
3 years ago
How do you solve P=3r+2s; for s?
EastWind [94]
P = 3r + 2s --> P - 3r = 3r - 3r + 2s
2s = P - 3r --> 2s/2 = (P - 3r)/2
s = (P - 3r)/2
8 0
3 years ago
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