Answer:- 47.62 mL
Solution:- It is a dilution problem where we are asked to calculate the volume of 15.75 M perchloric acid solution required to make 500.0 mL of 1.500 M solution.
For solving this type of problems we use the dilution equation:
Where, 
is the concentration of the concentrated solution and 
is it's volume.
is the concentration of the diluted solution and 
is it's volume. Let's plug in the values in the equation and solve it for .
On rearranging this for :
So, 47.62 mL of 15.75 M perchloric acid are required to make 500.0mL of 1.500 M solution.
Answer:
B. The carbons on either side of the double bond are Pointed in opposite directions
Answer:
HgBr₂.
Explanation:
- To determine the empirical formula of the mercury bromide that is produced, we should calculate the no. of moles of Hg (1.750 g) and Br (1.394 g) used to prepare the mercury bromide.
no. of moles of Hg = mass/atomic mass = (1.75 g)/(200.59 g/mol) = 0.00872 mol.
no. of moles of Br = mass/atomic mass = (1.394 g)/(79.904 g/mol) = 0.01744 mol.
- We divide by the lowest no. of moles (0.00872) to get the mole ratio:
The mole ratio of (Br: Hg) is: (2: 1).
<em>So, the empirical formula is: HgBr₂.</em>
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Option (D) Short distance
To standardize 20.00 mL of 0.495 M H₂SO₄ are used 44.10 mL of 0.450 M NaOH in a neutralization reaction.
We want to standardize a H₂SO₄ solution with NaOH. The neutralization reaction is:
H₂SO₄ + 2 NaOH ⇒ Na₂SO₄ + H₂O
The buret, which contains NaOH, reads initially 0.63 mL, and 44.73 mL at the endpoint. The used volume of NaOH is:
44.10 mL of 0.450 M NaOH are used for the titration. The reacting moles of NaOH are:
The molar ratio of H₂SO₄ to NaOH is 1:2. The moles of H₂SO₄ that react with 0.0198 moles of NaOH are:
0.00990 moles of H₂SO₄ are in 20.00 mL of solution. The molarity of H₂SO₄ is:
![[H_2SO_4] = \frac{0.00990mol}{0.02000} = 0.495 M](https://tex.z-dn.net/?f=%5BH_2SO_4%5D%20%3D%20%5Cfrac%7B0.00990mol%7D%7B0.02000%7D%20%3D%200.495%20M)
To standardize 20.00 mL of 0.495 M H₂SO₄ are used 44.10 mL of 0.450 M NaOH in a neutralization reaction.
Learn more: brainly.com/question/2728613
