Explanation:
The atoms of one element differs from the atoms of other elements in terms of the number of protons they contain. This is often taken as the atomic number of such an atom.
- The number of proton is the best indicator of the atom one is dealing with.
- Based on this number, elements are categorized into distinct columns and rows on the periodic table.
- The atomic number is the number of protons or positively charge particles in the atom.
II.
It is possible to change the identity of an atom. This is only possible by altering the atomic number of the atom.
Only nuclear reactions have this capability.
When an atom undergoes nuclear reaction that involves change in number of protons, transmutation occurs and a new atom forms.
Answer:
D. MgO
Explanation:
We need to look at the charge of element. (Look at a periodic table for this)
Mg, which is Magnesium, has a charge of 2+ because it's in the second column, or group, from the left.
O, which is Oxygen, has a charge of 2- because it's in the second column, or group, from the right.
Since Mg is 2+, it's the cation and since O is 2-, it's the anion. We can put these two elements together into an ionic compound.
Mg^(2+) and O^(2-) becomes Mg2O2, where we can cancel the 2s: MgO.
Thus, the answer is D.
Hope this helps!
Answer:
The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is
Explanation:
Given :
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:
= Rydberg energy
n = principal quantum number of the orbital
Energy of 11th orbit =
Energy of 10th orbit =
Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.
(Planck's' equation)
The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is
Line one: 4h atoms and 2o atoms on reactant and product side.
Line two: 4fe atoms 6o atoms on reactant and product side.
Line three: 2cl atoms, 2na atoms and 2br atoms on both the reactant and product side.