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3 years ago

Ano ang kahalagahan ng pelikula o doyu film sa manonood

1 answer:

3 0

Ang paglaganap ng mga pelikula ay nagdudulot ng positibo at negatibong epekto nito sa mga mag-aaral. Dahil sa pelikula nakikita at natutuklasan ay kultura ng mga iba’t ibang bansa. Dahil dito nalilinang at lumalawak ang kaalaman sa mga kultura. Kinagigiliwan ng marami ang panonood ng pelikula dahil nakakuha sila ng mga aral at mga bagong kaalaman.

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Please help me out here please

zepelin [54]

I would say G sorry if it’s not right

3 0

3 years ago

Read 2 more answers

A sample of 53.0 of carbon dioxide was obtained by heating 1.31 g of calcium carbont. What is the percent yield for this reactio

MaRussiya [10]

Answer:

92.04%

Explanation:

Given:

Mass of CO₂ obtained = 53.0 grams

Mass of calcium carbonate heated = 1.31 grams

Now,

the molar mass of the calcium carbonate = 100.08 grams

The number of moles heated in the problem = Mass / Molar mass

= (1.31 grams) / (100.08 grams/moles)

= 0.013088 moles

now,

1 mol of calcium carbonate yields 1 mol of CO₂

thus,

0.013088 moles of calcium carbonate will yield = 0.013088 mol of CO₂

now,

Theoretical mass of 0.013088 moles of CO₂ will be

= Number of moles × Molar mass of CO₂

= 0.013088 × 44 = 0.5758 grams

Thus, the percent yield for this reaction = $\frac{\textup{Actual yield}}{\textup{Theoretical yield}}\times100$

the percent yield for this reaction = $\frac{0.53}{0.5758}\times100$

the percent yield for this reaction = 92.04%

6 0

3 years ago

A quantity of 0.225 g of a metal M (molar mass = 27.0 g/mol) liberated 0.303 L of molecular hydrogen (measured at 17°C and 741 m

Lana71 [14]

Answer:

Oxide of M is $M_2O_3$ and sulfate of $M_2(SO_4)_3$

Explanation:

0.303 L of molecular hydrogen gas measured at 17°C and 741 mmHg.

Let moles of hydrogen gas be n.

Temperature of the gas ,T= 17°C =290 K

Pressure of the gas ,P= 741 mmHg= 0.9633 atm

Volume occupied by gas , V = 0.303 L

Using an ideal gas equation:

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.9633 atm\times 0.303 L}{0.0821 atm L/mol K\times 290 K}=0.01225 mol$

Moles of hydrogen gas produced = 0.01225 mol

$2M+2xHCl\rightarrow 2MCl_x+xH_2$

Moles of metal = $\frac{0.225 g}{27.0 g/mol}=8.3333 mol$

So, 8.3333 mol of metal M gives 0.01225 mol of hydrogen gas.

$\frac{8.3333}{0.01225 mol}=\frac{2}{x}$

x = 2.9 ≈ 3

$2M+6HCl\rightarrow 2MCl_3+3H_2$

$MCl_3\rightarrow M^{3+}+Cl^-$

Formulas for the oxide and sulfate of M will be:

Oxide of M is $M_2O_3$ and sulfate of $M_2(SO_4)_3$ .

3 0

3 years ago

The density of ethanol is 0.789 g/cm^3 at 20 degrees C. What volume of ethanol has a mass of 15.5 grams?

lys-0071 [83]

<span>density = mass / volume

given the quotient , we have density and mass, volume can be easily calculated as:

volume = mass / p =15.5 g / 0.789 g/cm^3

=~ 20 cm^3 (dimension ally constant)</span>

6 0

3 years ago

What is the correct formula for xenon hexafluoride? XeF XeF6 Xe6F6 Xe6F

Vinil7 [7]

Hexa- means six
"hexa-" and it is in front of the fluoride so that means we have 6 fluorines
Answer:
xenon hexafluoride → $XeFl_{6}$

Any questions?

3 0

3 years ago

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Ano ang kahalagahan ng pelikula o doyu film sa manonood​

Ano ang kahalagahan ng pelikula o doyu film sa manonood