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Crank
3 years ago
15

First one help me help!!!!!

Mathematics
2 answers:
denis-greek [22]3 years ago
5 0
u can use photomath to find the answer
Vlad [161]3 years ago
3 0
The second one, vertical compression
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Uma empresa do ramo de confecções produz e comercializa calças jeans. Se x representa a quantidade produzida e comercializada (e
Semenov [28]

Answer:

I am in 5 classso i did not known answer

5 0
3 years ago
What is the solution to the equation 8 - 2b = -2/3(12b + 6)?
Delvig [45]
<span>8 - 2b = -2/3(12b + 6)
8 - 2b = -8b -4
8 + 4 = -8b + 2b
12 = -6b
b = -12/6
b = -2

So, your final answer is b = -2</span>
8 0
3 years ago
For a right triangle with legs a = 5 and b = 12, use the pythagorean theorem to find the hypotenuse,
kondor19780726 [428]

c = √(a²+b²)

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7 0
3 years ago
Find the least common denominator of the fractions 5/8, 1/18, 5/9, 9/14
OLga [1]
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It would be 494

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Hope this helps!
7 0
3 years ago
What are the missing parts that correctly complete the proof
bonufazy [111]

Answer:

2. \overline{AX}\cong \overline{BX}

3. PX \perp AB - definition of perpendicular

4. \angle PXA \cong \angle PXB - all right angles are congruent

6. \triangle AXP\cong \triangle BXP

7. \overline{PA} \cong \overline{PB}

Step-by-step explanation:

<u>Given: </u>Point P is the perpendicular bisector of AB

<u>Prove: </u>P is equidistant from the endpoints AB

<u>Proof.</u>

1. Point P is on the perpendicular bisector of AB - given

2.\overline{AX}\cong \overline{BX} - definition of bisector

3. PX \perp AB - definition of perpendicular

4.  \angle PXA \cong \angle PXB - all right angles are congruent

5. \overline{PX} \cong \overline{PX} - reflexive property of congruence

6. \triangle AXP\cong \triangle BXP - SAS congruency postulate

7. \overline{PA} \cong \overline{PB} - corresponding parts of congruent triangles are congruent

8. Point P is equidistant from the endpoints of AB - definition of equidistant

5 0
3 years ago
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