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olya-2409 [2.1K]
3 years ago
10

The ka value for acetic acid, ch3cooh(aq), is 1.8Ã 10â5 m. calculate the ph of a 1.40 m acetic acid solution.

Chemistry
1 answer:
kow [346]3 years ago
3 0
1) Equlibrium reaction

CH3COOH (aq) = CH3COO(-) (aq) + H(+) (aq)

2) Equilibrium constant

Keq = Ka = [CH3COO-] [H+] / [CH3COOH]

3) Equilibrium concentrations

                  CH3COOH      CH3COO-     H+

start               1.40                  0              0
react                  x                   0              0
produced           0                   x              x

equilibrium     1.40 - x            x               x

=> Ka = x * x / (1.40 - x)

Approximation: given that Ka is very small x <<< 1,40 and 1.40 - x  ≈ 1.40

=> Ka ≈ x^2 / 1.40

=> x^2 ≈ 1.40Ka = 1.40 * 1.8 * 10^ - 5 = 2.52 * 10^-5

=> x ≈ √(2.52 * 10^-5) ≈ 5.02 * 10^ -3 M

4) pH = log 1 / [H+]

[H+] = x = 5.02 * 10^-3M

=> pH ≈ log (1 / 5.02 * 10^-3) ≈ 2.3

Answer: 2.3
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you find that 7.36g of a compound has decomposed to give 6.93g of oxygen. the only other element in the compound is hydrogen. if
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First solve the moles of oxgen present in the compound

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then solve the moles of hydrogen present
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so the O and H are in the same mole content so the molecular formula would be OH, but the molar mass will not satisfy. so the answer would be
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How manymoles of each ion are present in 175 mL of 0.147 M Fe2(SO4)3?
lilavasa [31]

Answer: 0.0257 moles of Fe^{3+}  and 0.0257 moles of SO_4^{2-}

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{moles}{\text {Volume in L}}

moles of  Fe_2(SO_4)_3=Molarity\times {\text {Volume in L}}=0.147\times 0.175L=0.0257moles

The balanced reaction for dissociation will be:

Fe_2(SO_4)_3\rightarrow Fe^{3+}+SO_4^{2-}

According to stoichiometry:  

1 mole of Fe_2(SO_4)_3 gives 1 mole of Fe^{3+}  and 1 mole of SO_4^{2-}

Thus there will be 0.0257 moles of Fe^{3+}  and 0.0257 moles of SO_4^{2-}

8 0
4 years ago
If 156 grams of chromium react with an excess of oxygen, as shown in the balanced chemical equation below, how many grams of chr
Sunny_sXe [5.5K]

Answer:

=759.95 grams.

Explanation:

The molar mass of chromium is 51.9961 g/mol

Therefore the number of moles of chromium in 156 grams is:

Number of moles =mass/RAM

=156g/51.9961g/mol

=3 moles.

From the equation provided, 3 moles of chromium metal produce 2 moles of Chromium oxide.

Therefore 3 moles of chromium produce:

(3×2)/4 moles =1.5 moles of chromium oxide.

I mole of chromium oxide has a mass of 151.99 g

Thus 1.5 moles= 1.5mole ×151.99 g/mol

=759.95 grams.

3 0
3 years ago
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