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Novay_Z [31]
4 years ago
9

Write complete ionic equation to show the reaction of aqueous hg2(no3)2 with aqueous sodium chloride to form solid hg2cl2 and aq

ueous sodium nitrate. express your answer as a chemical equation. identify all of the phases in your answer.
Chemistry
2 answers:
Naddik [55]4 years ago
6 0

First we start with our molecular equation to ensure all atoms are balanced in order to maintain the law of conservation of mass.

Hg_2(NO_3)_2_(_a_q_) + NaCl_(_a_q_) \implies Hg_2Cl_2_(_s_) + NaNO_3_(_a_q_).

The equation is unbalanced since we have 1 Cl atom on left hand side as opposed to 2 on the right hand side and we have 2 NO_3 molecules on left hand side and 1 on the right hand side. So we add a coefficient of 2 on  both the NaCl and NaNO_3

Hg_2(NO_3)_2_(_a_q_) + 2NaCl_(_a_q_) \implies Hg_2Cl_2_(_s_) + 2NaNO_3_(_a_q_)

The reaction occurs between solutes that are soluble in water to give a solid as a precipitate. So the complete ionic equation will show the soluble compounds in their dissociated states as ions in water and the insoluble compound as a solid.

2Hg^+_(_a_q_) + 2NO_3^-_(_a_q_) + 2Na^+_(_a_q_) + 2Cl^- _(_a_q_) \implies Hg_2Cl_2_(_s_) + 2Na^+_(_a_q_) + 2NO_3^-_(_a_q_)

Andrews [41]4 years ago
5 0
<span>Answer: Hg2(NO3)2 + 2 NaCl --------> Hg2Cl2 + 2 NaNO3 Hg2+2 + 2NO3-1 + 2Na+ Cl- ----> Hg2Cl</span>
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3 years ago
2C6H5COOH + 15O2 → 14CO2 + 6H2O which of the following options gives the correct product:product ratio?
mash [69]
You did not include the options but I can tell you the product ratio.

The product ratio is the mole ratio of the products of the reaction.

From the balanced chemical equation you have all the mole ratios:

The given equation is: 2 C6H5COOH + 15O2 --> 14 CO2 + 6H2O

The mole ratios are: 2 C6H5COOH: 15 O2: 14 CO2 : 6 H2O

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Their mole ratio = 14 CO2 : 6 H2O

That can be expressed as:

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----------------- =  -----------------
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It is also the same that:

6 mol H2O : 14 mol CO2

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------------------ =  -------------------
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So, compare your options to the ratios show above and pick the proper ratio.
7 0
4 years ago
You have an unknown quantity of oxygen at a pressure of 2.2 atam, a volume of 21 liters and a temperature of 87 Celsius. How man
laila [671]

<span>Let's assume that the oxygen gas has ideal gas behavior. 
Then we can use ideal gas formula,
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Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol⁻¹ K⁻¹) and T is temperature in Kelvin.

<span>
P = 2.2 atm = 222915 Pa
V = 21 L = 21 x 10</span>⁻³ m³

n = ?

R = 8.314 J mol⁻¹ K⁻¹

<span> T = 87 °C = 360 K

By substitution,
</span>222915 Pa x 21 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻<span>¹ x 360 K
                                       n = 1.56</span><span> mol</span>

<span>
Hence, 1.56 moles of the oxygen gas are </span><span>left for you to breath.</span><span>
</span>
6 0
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