Answer:
- Not balanced.
- Reactants: Zn and HCI
.
- Products: ZnCl₂ and H₂.
- Substitution reaction.
Explanation:
Hello,
In this case, for the given reaction:
Zn + HCI → ZnCl₂ + H₂
We can see that it is not balanced due to the fact that at the left side we have one hydrogen atom whereas at the right side two, taking into account the number must be same as well as chlorine. Thus, in order to balance we write:
Zn + 2HCI → ZnCl₂ + H₂
And that is enough. Moreover, we can see that the chemical species at the left side of the equation are the reactants and those at the right side the products, thus we have:
Reactants: Zn and HCI
.
Products: ZnCl₂ and H₂.
Finally, since we can see that the chlorine is at the reactants with hydrogen, but at the end with the zinc, and the initial zinc is alone as well as the yielded hydrogen we can infer this is a substitution reaction.
Best regards.
The three main types of lipids are triglycerides, steroids and phospholipids
Answer: I HOPE THIS HELPS, HAVE A GREAT EARLY HALLOWEEN
Explanation:
PubChem CID: 1084
Molecular Formula: S2O3(2−) or O3S2-2
Synonyms: Thiosulphate THIOSULFATE ION sulfurothioate UNII-LLT6XV39PY Thiosulfate (S2O32-) More...
Molecular Weight: 112.13 g/mol
Answer:
O Continental-continental convergent boundary
Explanation:
Hope it helps.
Answer:
Option(II) and option (IV) are correct.
Explanation:
Here products are
and
and reactant is 
(I) According to Le-chatelier principle,increase in
will shift the equilibrium towards reactant side to keep the equilibrium constant unchanged.
(II) According to Le-chatelier principle,decrease in
will shift the equilibrium towards product side to keep the equilibrium constant unchanged.
(III) Adding a catalyst will not change position of equilibrium. Catalyst only helps to achieve equilibrium in a lesser time.
(IV) As this reaction is an endothermic reaction therefore heat is consumed in formation of product. Therefore increase in temperature will lead to formation of more product to consume excess heat added.
(V) Pure solids and liquids do not affect position of equilibrium as their concentrations remain unchanged.