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grigory [225]
4 years ago
5

Help me find it plz!​

Chemistry
1 answer:
natali 33 [55]4 years ago
3 0

Answer:

a)O2

b)CaO+CO2

c)NH3

d)NaCl+H2O

e)ZnSO4+H2

f)Cacl2+2H2O

g) Cl2

Explanation:

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I assume this is a true or false question. I would say true

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A scientist produces zinc iodide (zni2). (a) calculate the minimum mass of zinc that needs to be added to 0.500 g of iodine so t
harina [27]

The minimum mass of Zinc, Zn that needs to be added to 0.500 g of iodine so that the iodine fully reacts is 0.128 g

<h3>Balanced equation </h3>

Zn + I₂ —> ZnI₂

Molar mass of Zn = 65 g/mol

Mass of Zn from the balanced equation = 1 × 65 = 65 g

Molar mass of I₂ = 127 × 2 = 254 g/mol

Mass of I₂ from the balanced equation = 1 254 = 254 g

SUMMARY

From the balanced equation above,

254 g of I₂ required 65 g of Zn

<h3>How to determine the mass of Zn needed </h3>

From the balanced equation above,

254 g of I₂ required 65 g of Zn

Therefore,

0.5 g of I₂ will require = (0.5 × 65) / 254 = 0.128 g of Zn

Thus, the minimum mass of Zn required is 0.128 g

Learn more about stoichiometry:

brainly.com/question/14735801

4 0
2 years ago
For the reaction represented by the equation 2KClO3 → 2KCl + 3O2, how many grams of potassium chlorate are required to produce 1
Vikentia [17]

 The grams  of potassium chlorate  that are required  to produce 160 g of oxygen  is   408.29  grams

 

<u><em>calculation</em></u>

 2 KClO₃→  2 KCl  + 3O₂

Step 1:  find the  moles of  O₂

moles  =  mass÷  molar mass

from periodic table  the  molar mass of O₂  = 16 x2 = 32 g/mol

moles  = 160 g÷ 32  g/mol =  5 moles

Step2 : use the  mole   ratio to determine the  moles of KClO₃

from equation given KClO₃ : O₂  is 2:3

therefore the v moles of KClO₃  =  5 moles x 2/3 = 3.333  moles


Step 3:  find the mass  of KClO₃

mass= moles x molar mass

from periodic table  the molar mass of KClO₃

= 39 + 35.5 + (16 x3) =122.5 g/mol


mass  = 3.333 moles x 122.5 g/mol =408.29 grams

7 0
3 years ago
An ion with 5 protons, 6 neutrons, and a charge of 3+ has an atomic number of
user100 [1]

Answer:1. 5

Explanation: the element is boron and the atomic number is 5

6 0
3 years ago
For most solids at room temperature, the specific heat is determined by oscillations of the atom cores in the lattice (each osci
Cloud [144]

Answer:

The specific heat of copper is  C= 392 J/kg\cdot ^o K

Explanation:

From the question we are told that

The amount of energy contributed by each oscillating lattice site  is  E =3 kT

       The atomic mass of copper  is  M =  63.6 g/mol

        The atomic mass of aluminum is  m_a = 27.0g/mol

        The specific heat of aluminum is  c_a = 900 J/kg-K

 The objective of this solution is to obtain the specific heat of copper

       Now specific heat can be  defined as the heat required to raise the temperature of  1 kg of a substance by  1 ^o K

  The general equation for specific heat is  

                    C = \frac{dU}{dT}

Where dT is the change in temperature

             dU is the change in internal energy

The internal energy is mathematically evaluated as

                       U = 3nk_BT

      Where  k_B is the Boltzmann constant with a value of 1.38*10^{-23} kg \cdot m^2 /s^2 \cdot ^o K

                    T is the room temperature

                      n is the number of atoms in a substance

Generally number of  atoms in mass of an element can be obtained using the mathematical operation

                      n = \frac{m}{M}  * N_A

Where N_A is the Avogadro's number with a constant value of  6.022*10^{23} /  mol

          M is the atomic mass of the element

           m actual mass of the element

  So the number of atoms in 1 kg of copper is evaluated as  

             m = 1 kg = 1 kg *  \frac{10000 g}{1kg }  = 1000g

The number of atom is  

                       n = \frac{1000}{63.6} * (6.0*0^{23})

                          = 9.46*10^{24} \ atoms

Now substituting the equation for internal energy into the equation for specific heat

          C = \frac{d}{dT} (3 n k_B T)

              =3nk_B

Substituting values

         C = 3 (9.46*10^{24} )(1.38 *10^{-23})

            C= 392 J/kg\cdot ^o K

5 0
3 years ago
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