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Novay_Z [31]
3 years ago
10

The strength of a rectangular beam varies jointly with its width and the square of its thickness. if a beam 7 7 inches wide and

3 3 inches thick supports 2520 2520 ​pounds, how much can a beam of the same material that is 2 2 inches wide and 1 1 inch inch thick​ support?
Mathematics
1 answer:
Ugo [173]3 years ago
3 0
To solve the joint variation question we proceed as follows:
let the strength be p, the width be w, and thickness be t.
thus:
p=kwt
where k is the constant of proportionality.
p=2520 when w=7 and t=3
thus
2520=7*3*k
hence
k=120
thus the formula for variation is:
p=120wt
hence the value of p when w=2 in and t=1 in will be:
p=120*2*1
p=240 pounds

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The answer is

<h2>\sqrt{29}  \:  \:  \: or \:  \:  \:5.38 \:  \:  \: units</h2>

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|AB|  =  \sqrt{ ({1 - 6})^{2} +  ({3 - 5})^{2}  }  \\  =  \sqrt{ ({ - 5})^{2}  + ( { - 2})^{2} }  \\  =  \sqrt{25 + 4}  \\  =  \sqrt{29}

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\sqrt{29}  \:  \:  \: or \:  \:  \:5.38 \:  \:  \: units

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