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Novay_Z [31]
3 years ago
10

The strength of a rectangular beam varies jointly with its width and the square of its thickness. if a beam 7 7 inches wide and

3 3 inches thick supports 2520 2520 ​pounds, how much can a beam of the same material that is 2 2 inches wide and 1 1 inch inch thick​ support?
Mathematics
1 answer:
Ugo [173]3 years ago
3 0
To solve the joint variation question we proceed as follows:
let the strength be p, the width be w, and thickness be t.
thus:
p=kwt
where k is the constant of proportionality.
p=2520 when w=7 and t=3
thus
2520=7*3*k
hence
k=120
thus the formula for variation is:
p=120wt
hence the value of p when w=2 in and t=1 in will be:
p=120*2*1
p=240 pounds

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Andre45 [30]

Given that speed of the cyclist = 36 kilometers per hour.

Now question says to find the speed in meters per second.

We know that 1 kilometer = 1000 meter

and 1 hour = 3600 seconds

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36*1000/3600

=36*10/36

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3 years ago
1) Write an absolute value equation that is reflected, vertically shifted 2/3 units down and 1/2 units to the right.
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Question 1) Write an absolute value equation that is reflected, vertically shifted 2/3 units down and 1/2 units to the right.

Answer 1):

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reflection happens when we multiply by negative sign so we get

y=-|x|

To get vertical shift down, we subtract so new equation is

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4 0
3 years ago
4^2/4^6<br><br> Options:<br> 4^-3<br> 4^3<br> 4^-4<br> 4^4
Vlad [161]
Hello!

The rule regarding the division of exponents states the following:

\frac{ B^{x} }{ B^{y} } = B^{x-y}

Insert any known values into the formula above:

\frac{ 4^{2} }{ 4^{6} } = 4^{2-6}

Simplify the expression:

4^{2-6} = 4^{-4}

We have now proven that \frac{ 4^{2} }{ 4^{6} } is equal to 4^{-4}.

I hope this helps!
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Need help with this please
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Answer:

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Step-by-step explanation:

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