Question

Your car is stalled in the middle of a large patch of ice (assumed to be frictionless). You have a friend that has thrown a rope to you and you attach it to the car.Your friend then applies a continuous horizontal force of 550 N to you and the car. If you and the car have a total mass of 1430 kg, how long will it take for you to reach

Answer 1

Answer:

The time depends on the distance that they have to travel

$x(t) = \frac{0.3846t^{2} }{2}$

Explanation:

The only horizontal force exerts over the car and you, it is the force that your friend is applied

Newton's Second Law of Motion defines the relationship between acceleration, force, and mass, thus

$\sum{F} = ma$

        550 = 1430a

            a = 0.3846 m/s2

             

The car and you have a motion under constant acceleration, then theirs position to a time-based is:

$x(t) = x_{0} + v_{0}t +\frac{at^{2} }{2}$

By the initial conditions

$x(t) = \frac{at^{2} }{2}$

$x(t) = \frac{0.3846t^{2} }{2}$

The time depends on the distance that they have to travel