Which of the following creates an adhesive force that prevents separation of the parietal and visceral pleurae during ventilatio
1 answer:
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Answer:
The minimum difference between the lengths of the two tubes should be 0.385 meters.
Explanation:
As we known that for any two waves to arrive in phase at any point the difference in the path traveled by the waves should be an integral multiple of the wavelength of the wave.
Mathematically we can write:
For the given wave we have
Applying values we get
Thus the minimum difference in the lengths of the tubes can be obtained by putting the value of n = 1
Good afternoon!
We can see that
The index of refraction can be calculated as:
As we noted,
, and therefore:
Beccause n = c/v, we have:
n > 1
B - Is more than 1.
We can see that
The index of refraction can be calculated as:
As we noted,
Beccause n = c/v, we have:
n > 1
B - Is more than 1.