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Salsk061 [2.6K]
3 years ago
14

Which activity best demonstrates Ernest Rutherford's creativity?A. questioning the correctness of the plum pudding modelB. desig

ning an experiment to test the plum pudding modelC. making observations about the gold foil experimentD. summarizing the conclusions from the gold foil experiment as a theory
Physics
1 answer:
Rus_ich [418]3 years ago
5 0

Answer:

C.

Explanation:

Of the following activity best demonstrates the creativity of Rutherford: is making observations about the gold foil experiment.  

Rutherford's Gold Foil Test confirmed the existence of a thin, enormous atom core that would later be recognized as an atom's nucleus. To examine the effect of alpha particles on material, Ernest Rutherford, Hans Geiger and Ernest Marsden conducted their Gold Foil Experiment.

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If a point charge is located at the center of a cylinder and the electric flux leaving one end of the cylinder is 20% of the tot
zheka24 [161]

The portion of the flux leaves the curved surface of the cylinder is 60%.

<h3 /><h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

If a point charge is located at the center of a cylinder and the electric flux leaving one end of the cylinder is 20% of the total flux leaving the cylinder.

If 20% of the flux leave from one end, then another 20% will leave from another end.

So, the net flux through curved surface is

100 -20 -20 = 60%

Thus, the total flux  leaves the curved surface of the cylinder is 60%

Learn more about electrons.

brainly.com/question/1255220

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5 0
2 years ago
A rocket is being launched straight up. Air resistance is not negligible.
Yanka [14]

Answer:

hope this will help you

have a great day

3 0
2 years ago
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A(n) 55.5 g ball is dropped from a height of 53.6 cm above a spring of negligible mass. The ball compresses the spring to a maxi
Serggg [28]

Answer:

The spring force constant is  k=243\ \frac{N}{m} .

Explanation:

We are told the mass of the ball is m=0.0555\ kg, the height above the spring where the ball is dropped is h=0.536\ m,  the length the ball compresses the spring is d=0.04897\ m and the acceleration of gravity is 9.8\ \frac{m}{s^{2}} .

We will consider the initial moment to be when the ball is dropped and the final moment to be when the ball stops, compressing the spring. We supose that there is no friction so the initial mechanical energy E_{mi} is equal to the final mechanical energy E_{mf} :

                                                    E_{mf}=E_{mi}

Initially there is only gravitational potential energy because the force of the spring isn't present and the speed is zero. In the final moment there is only elastic potential energy because the height is zero and the ball has stopped. So we have that:

                                                   \frac{1}{2}kd^{2}=mgh

If we manipulate the equation we have that:

                                                    k=\frac{2mgh}{d^{2} }

                                         k=\frac{2\ 0.0555\ kg\ 9.8\frac{m}{s^{2}}\ 0.536\ m}{(0.04897)^{2}m^{2}}

                                              k=\frac{0.58306\ \frac{kgm^{2}}{s^{2}}}{2.398x10^{-3}m^{2}}

                                                     k=243\ \frac{N}{m}

                                                   

                             

5 0
4 years ago
Impulse equals?<br> A) momentum x velocity<br> B) momentum x time<br> C) mass x velocity
mina [271]

Answer:

B

Explanation:

The impulse experienced by an object is the force•time.

7 0
3 years ago
Read 2 more answers
A car travels 45 km due north and 70 km west. What is the car's displacement?
Elis [28]

Answer:

A

Explanation:

7 0
3 years ago
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