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3 years ago

Does the depth of a pot affect how water freezes

2 answers:

8 0

The depth of the pot affects how the water freezes. I say this because the lower the pot goes, pressure increases. When there is an increase in pressure, the boiling point increases, while the freezing point reduces. Ands if the pressire reduces, the boiling point reduces and freezing point increases. Hope i helped. Have a nice day.

Iteru [2.4K]3 years ago

3 0

In my opinion it does. The more water the pot holds, the longer you need to wait for it to freeze. Since there is more water, some parts may not be completely frozen. An experiment you can try is to get an ice cube container and a pot. fill both of them and put them in the freezer for the same amount of time. When you take it out, the ice cubes should be frozen leaving the pot with cold water.

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What is the average power supplied by a 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s?

Alchen [17]

A 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s has an average power of 560 W (Option b).

<h3>What is power?</h3>

Power is the work done over a period of time.

A secretary with a mass (m) of 60.0 kg runs up a 4.0 m (d) tall flight of stairs. Given gravity (g) is 9.81 m/s², the work (W) done is:

W = m × g × d = 60.0 kg × 9.81 m/s² × 4.0 m = 2.35 × 10³ J

They do 2.4 × 10³ J of work in 4.2 s (t). The average power (P) is:

P = W / t = 2.35 × 10³ J / 4.2 s = 560 W

A 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s has an average power of 560 W (Option b).

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2 years ago

the resolution of a camera or other optical system is determined by the relationship between what two scales?

Triss [41]

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The distance between the crests or troughs of a wave motion is referred to as the wavelength () of light. 2. Frequency (f) - The frequency of a repeated event is the number of instances per unit of time. Frequency in the context of light is the number of wavelength repetitions per second.

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2 years ago

2. A common physics experiment involves lowering an open tube into a cylinder of water and moving the tube up and down to adjust

notsponge [240]

Answer:

Explanation:

This question pertains to resonance in air column. It is the case of closed air column in which fundamental note is formed at a length which is as follows

l = λ / 4 where l is length of tube and λ is wave length.

here l = .26 m

λ = .26 x 4 = 1.04 m

frequency of sound = 330 Hz

velocity of sound = frequency x wave length

= 330 x 1.04

= 343.2 m /s

b )

Next overtone will be produced at 3 times the length

so next length of air column = 3 x 26

= 78 cm

c )

If frequency of sound = 256 Hz

wavelength = velocity / frequency

= 343.2 / 256

= 1.34 m

= 134 cm

length of air column for resonance

= wavelength / 4

134/4

= 33.5 cm

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3 years ago

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