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3 years ago

Why are objects that fall near Earth's surface rarely in free fall?

Physics

1 answer:

sveta [45]3 years ago

6 0

Answer: Air exerts forces on falling objects near Earth's surface.

Explanation: Objects falling near the earth surface are rarely in free fall due to the force exerted by air on falling object near the earth( air resistance).

The acceleration of free fall tend to pull the body towards the earth surface while air resistance (drag) tends to act in the opposite direction.

Given that the weight of the body is always constant.

The drag acts in the upward direction, thereby negating the downward weight of the object.

From Newton's Second law:

Force = mass × acceleration due to gravity

Acceleration = force / mass

The net force acting on the object becomes :

(Downward weight - upward drag)

This hampers the free fall of the object due to gravity.

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If pressure is increased from 200 kPa to 300 kPa, and the original volume of gas was 1.5 L, what is the new volume? Assume the t

Oxana [17]

Answer:

The answer to your question is: V2 = 1 l

Explanation:

Data

P1 = 200 kPa

P2 = 300 kPa

V1 = 1.5 l

V2 = ?

Formula

P1V1 = P2V2

V2 = (P1V1) / P2

V2 = (200 x 1.5) / 300

V2 = 1 l

6 0

3 years ago

The mass of a large car is 1000 kg. How much force would be required to accelerate the car at a rate of 3msec2

pogonyaev

Answer:

3000 N

Explanation:

We have,

• Mass, m = 1000 kg

• Acceleration, a = 3 m/s²

We have to find force required, F.

$\longrightarrow$ F = ma

$\longrightarrow$ F = 1000 × 3 N

$\longrightarrow$ F = 3000 N (Answer)

8 0

2 years ago

During an all-night cram session, a student heats up a 0.577 liter (0.577 x 10- 3 m3) glass (pyrex) beaker of cold coffee. initi

krok68 [10]

Here coffee is filled into a glass cup and when it is heated expansion of coffee as well as glass occurs

we will find the change in volume of glass cup and change in the volume of coffee.

volume expansion is calculated by

$\Delta V = V_o \gamma \Delta T$

for pyrex glass we have

$\gamma = 4 * 10^{-6}$

now by the formula

$\Delta V = 4* 10^{-6} * 0.577 * (91.3 - 15.8)$

$\Delta V = 0.174 mL$

Now for the expansion of coffee

$\gamma = 2.14 * 10^{-4}$

now the expansion of coffee will be

$\Delta V = 2.14 * 10^{-4}* 0.577* (91.3 - 15.8)$

$\Delta V = 9.32 mL$

now the coffee that will spill out of the cup will be

$\Delta V = 9.32 mL - 0.174 mL$

$\Delta V = 9.15 mL$

so 9.15 mL coffee will spill out of the cup

5 0

3 years ago

Look at the circuit diagram. Which of these components is part of the circuit

Aneli [31]

You have not provided choices, therefore, I can not provide an exact choice.

However, I will tell you the components of the given circuit and you can choose the one found in the choices you have.

The given circuit is composed of:
1- A battery:
It has the symbol of the long line and short line next to each other. The long line represents the positive pole while the short line represents the negative one. Battery is used to supply power to the circuit
2- An ammeter:
If has the symbol of an "A" in a circle. This device is used to measure the current flowing in the circuit
3- A resistance:
It has the symbol of the zigzag line. Resistance could be any device that consumes the power in the circuit.
4- A switch:
This has the symbol of the line at the bottom of the circuit. In its current status, the switch is off which means that no current is flowing in the circuit. If we connect the open terminal of the switch with the circuit, the switch is said to be on and current would flow in the circuit.

Hope this helps :)

7 0

3 years ago

Read 2 more answers

A spherically spreading EM wave comes from an 1800-W source. At a distance of 5.0 m, what is the intensity, and what is the rms

babymother [125]

Answer:

The intensity of the EM wave is 5.729 W/m²

The rms value of the electric field is 46.452 V/m

Explanation:

Given;

power of the electromagnetic wave, P = 1800 W

The intensity of light is given by;

I = P / A

Where;

A is the surface area of the sphere = 4πr²

A is the surface area of the sphere = 4π(5)²

A is the surface area of the sphere = 314.2 m²

The intensity is calculated as;

I = P / A

I = (1800) / (314.2)

I = 5.729 W/m²

The rms value of the electric field is given by;

$E_{rms} = \sqrt{\frac{I}{c \epsilon _o}}\\\\E_{rms} = \sqrt{\frac{5.729}{(3*10^8)( 8.85*10^{-12})}}\\\\E_{rms} = 46.452 \ V/m$

8 0

4 years ago