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MrRissso [65]
3 years ago
11

Why are objects that fall near Earth's surface rarely in free fall?

Physics
1 answer:
sveta [45]3 years ago
6 0

Answer: Air exerts forces on falling objects near Earth's surface.

Explanation: Objects falling near the earth surface are rarely in free fall due to the force exerted by air on falling object near the earth( air resistance).

The acceleration of free fall tend to pull the body towards the earth surface while air resistance (drag) tends to act in the opposite direction.

Given that the weight of the body is always  constant.

The drag acts in the upward direction, thereby negating the downward weight of the object.

From Newton's Second law:

Force = mass × acceleration due to gravity

Acceleration = force / mass

The net force acting on the object becomes :

(Downward weight - upward drag)

This hampers the free fall of the object due to gravity.

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Explain two applications of resonance<br><br>PLEASEEEE HELP ME! ​
Tamiku [17]

Answer:

in physics, resonance is a phenomenon in which a vibrating system or external force drives another system to oscillate with greater amplitude at specific frequencies. example a familiar example is a playground swing, which acts as a pendulum.

hope this helped!

4 0
3 years ago
Salmon often jump waterfalls to reach their
Dafna11 [192]

The problem corresponds to the motion of a projectile (the salmon), with initial speed v_0, initial direction \theta=37.6^{\circ} and vertical acceleration g=9.81 m/s^2 downward. The two equations which gives the horizontal and vertical position of the salmon at time t are

S_x (t) = v_0 cos \theta t (1)

S_y (t) = v_0 sin \theta t - \frac{1}{2}gt^2 (2)

We can solve the problem by requiring Sx=3.16 m and Sy=0.379 m, the data of the problem.

Solving eq.(1) for t:

t=\frac{S_x}{v_0 cos \theta}

And substituting this expression of t into eq.(2), we get the following expression for v_0:

v_0 =\sqrt{\frac{g S_x^2}{2(tan \theta S_x -S_y)cos^2 \alpha}}

And substituting the numbers into the equation, we find

v_0 = 6.16 m/s

8 0
3 years ago
Which statement about the mass and the weight of an object is correct?
Fantom [35]

Answer:

HOPE IT HEPLED U !!!!

Explanation:

i think it's (C) They have different units ....

8 0
3 years ago
Why do you have to use a referance point to determine whether or not an object is in motion
SOVA2 [1]
Because there's no such thing as "really" moving.  
ALL motion is always relative to something.

Here's an example:
You're sitting in a comfy cushy seat, reading a book and listening 
to your .mp3 player, and you're getting drowsy.  It's so warm and 
comfortable, your eyes are getting so heavy, finally the book slips 
out of your hand, falls into your lap, and you are fast asleep.

-- Relative to you, the book is not moving at all.
-- Relative to the seat, you are not moving at all.
-- Relative to the wall and the window, the seat is not moving at all. 
-- But your seat is in a passenger airliner.  Relative to people on the 
    ground, you are moving past them at almost 500 miles per hour !
-- Relative to the center of the Earth, the people on the ground are moving
   in a circle at more than 700 miles per hour.   
-- Relative to the center of the Sun, the Earth and everything on it are moving
   in a circle at about 66,700 miles per hour !  

How fast are they REALLY moving ?
There's no such thing.
It all depends on what reference you're using. 
4 0
3 years ago
Read 2 more answers
What would happen to the wavelength of a wave as the velocity is increased and the
slamgirl [31]

Answer: wavelength will increase

Explanation:

Velocity is directly proportional to wavelength,as the velocity is increased, wavelength is also increased

5 0
4 years ago
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