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Gnom [1K]
3 years ago
12

Three years ago, you purchased a stock at a price of $33.48. The stock paid annual dividends of $.60 per share. Today, the stock

is worth $35.20 per share. What is your holding period return?
Mathematics
1 answer:
mixas84 [53]3 years ago
5 0

Answer:

10.51%

Step-by-step explanation:

Data provided in the question:

Period Initial value = $33.48

Period end value = $35.20

Annual dividend paid = $0.60

Total time = 3 years

Therefore,

the total dividend paid i.e the income = 3 × $0.60 = $1.80

Now,

The holding period is given as:

= \frac{ \textup{Income + end period value - initial period value }}{\textup{initial period value}}\times100\%

= \frac{ \textup{1.80 + 35.20 - 33.48}}{\textup{33.48}}\times100\%

= \frac{ \textup{3.52}}{\textup{33.48}}\times100\%

= 10.51%

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eimsori [14]

Answer:

5.5

Step-by-step explanation:

2,3,3,4,5,7,8,8,8,10,10,12

The mean of this data is 7.5.  So what you are trying to figure out is the mean between 2 and 7.  Since that is 3 and 4 it would be 3.5.  So 3.5 is the Q1.  Now you have to figure out the mean between 8 and 12.  That is 9.  This is Q3.  You have to subtract 9-3.5 and that is the interquartile range. So 5.5 is the answer.  I hope that made sense.

6 0
2 years ago
What is the value of f(-4) in the piecewise function f(x)= -x-5 for -5<= x <= -2; -x^2+1 for -2<=x<=2; (x-3)^2+2 for
Alik [6]


We first need to pick the correct piece to use. In this case, we will use f(x) = -x-5 because -5<=-4.

Then, we use direct substitution:
f(-4) = -(-4) - 5
f(-4) = -1

5 0
3 years ago
Read 2 more answers
The ratio of kids to adults in a dollar store is 2:1. Suppose there is a total of 50 kids to adults. How many kids are there?
Taya2010 [7]
The correct answer is 71 kids
6 0
2 years ago
The area of a cross section through the center of a sphere is 46 square inches. Find the surface area of the sphere.
gavmur [86]

Answer:

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Step-by-step explanation:

The cross section through the center of a sphere is a circle whose radius is equal to the radius of the sphere.

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A_{circle} = \pi r^2

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r^2 = \dfrac{46}{\pi}

r = \sqrt{\dfrac{46}{\pi}}

r = 3.83 ~in.

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SA = 4 \times \pi \times (3.83)^2

SA = 184~in.^2

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Answer:

Step-by-step explanation:

Her score after the two competitions was 500

hope this answer helps you

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3 years ago
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