Answer:
0.7233
Step-by-step explanation:
We want to find the area between the z-scores z=-0.95 and z=1.25.
We first find the area to the left of each z-score, and subtract the smaller area from the bigger one.
For the area to the left of z=-0.95, we read -0.9 under 5 from the standard normal distribution table.
This gives P(z<-0.95)=0.1711
Similarly the area to the left of z=1.25 is
P(z<1.25)=0.8944
Now the area between the two z-scores is
P(-0.25<z<1.25)=0.8944-0.1711=0.7233
Answer:
6
Step-by-step explanation:
f(6) = -6 this is the value when the x value is 6
g(5) = -5 this is the value when the x value is 5
4 * f(6) -6*g(5)
4*-6 - 6* -5
-24 + 30
6
14^2 - 9^2 = a^2
Easy enough
14^2 = 196
9^2 = 81
196 - 81 = 115
The square root of 115 = 10.72
The third side is 10.72km
