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3 years ago

Choose ALL of the points that are solutions of the following system of linear inequalities shown below.

Mathematics

1 answer:

amid [387]3 years ago

3 0

Answer:

The answer to your question is A, D, F

Step-by-step explanation:

Process

1.- From the graph, determine which points are the solution to the inequalities.

The solution will be all those points where the three inequalities cross.

First line. Dotted blue line. We observe that the solution is all the points over this line.

Second line. Straight violet line. We observe that the solution is all the points below the inequality.

A. It is a solution

B. it is not a solution

C. It is not a solution

D. It is a solution

E. It is not a solution

F. It is a solution

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Each item produced by a certain manufacturer is independently of acceptable quality with probability 0.95. Approximate the proba

Diano4ka-milaya [45]

Answer:

The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

Step-by-step explanation:

Let X = number of items with unacceptable quality.

The probability of an item being unacceptable is, P (X) = p = 0.05.

The sample of items selected is of size, n = 150.

The random variable X follows a Binomial distribution with parameters n = 150 and p = 0.05.

According to the Central limit theorem, if a sample of large size (n > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.

The mean of this sampling distribution is: $\mu_{\hat p}= p=0.05$

The standard deviation of this sampling distribution is: $\sigma_{\hat p}=\sqrt{\frac{ p(1-p)}{n}}=\sqrt{\frac{0.05(1-.0.05)}{150} }=0.0178$

If 10 of the 150 items produced are unacceptable then the probability of this event is:

$\hat p=\frac{10}{150}=0.067$

Compute the value of $P(\hat p\leq 0.067)$ as follows:

$P(\hat p\leq 0.067)=P(\frac{\hat p-\mu_{p}}{\sigma_{p}} \leq\frac{0.067-0.05}{0.0178})=P(Z\leq 0.96)=0.8315$

*Use a z-table for the probability.

Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

5 0

3 years ago

To prepare for a bake-off, Luis used 590 grams of flour each day for 3 weeks. How many kilograms did Luis use in those 3 weeks?

Thepotemich [5.8K]

Answer: $12.39\ kg$

Step-by-step explanation:

Given

Luis used 590 gm of flour each day

If he continues to use it for 3 weeks

A week has 7 days; so 3 weeks have 21 days

The flour used in 21 days

$\Rightarrow 21\times 590\\\Rightarrow 12,390\ g\ \text{or}\ 12.39\ kg$

Thus, $12.39\ kg$ of flour is used in 3 weeks

7 0

3 years ago

Find the sum of the first 6 terms in the following series. 6+(-18)+54+(-162)

lapo4ka [179]

Step-by-step explanation:

6+(-18)+54+(-162)

6-18+54-162

-12+(-108)

-12-108

= -120

3 0

3 years ago

Read 2 more answers

2x-5 < 3 someone help

aliya0001 [1]

Answer: x < 4

Step-by-step explanation: Move the constant to the right (5). Simplify (3+5=8). Divide both sides (8/2 & 2/2).

3 0

3 years ago

Which of these is the algebraic expression for "5 less than 4 times some number?" (1 O a 5- 4y 4-5y Ос 5y - 4 o a 4y - 5

DerKrebs [107]

Answer:

4y-5 is the answer to this one. you are taking five away from the product of four and y

8 0

3 years ago