Answer:
y = 1 + 1/((x -1)(x -4))
Step-by-step explanation:
To get vertical asymptotes at 1 and 4, you need factors (x -1) and (x -4) in the denominator. As x approaches 1 or 4, one of these will approach zero, and the function value will approach infinity.
To get a horizontal asymptote of 1, the function must approach the value 1 when the value of x gets large (positive or negative). This can generally be accomplished by simply adding 1 to a fraction that approaches zero when x is large.
Here, we make the fraction be the one that gives the vertical asymptotes, and we simply add 1 to it.
... y = 1 + 1/((x -1)(x -4))
If you like, this can be "simplified" to ...
... y = (x² -5x +5)/(x² -5x +4)
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In this rational expression form, please note that the numerator and denominator have the same degree. That will be the case when there is a horizontal asymptote. (When a slant asymptote, the numerator degree is 1 higher than the denominator.) The ratio of the coefficients of the highest degree terms is the horizontal asymptote value (or the slope of a slant asymptote).
A rectangular prism is a polyhedron with six rectangular faces. To fully define a rectangular prism, one must know its length, width and height. The volume of a rectangular prism is expressed as the product of its dimensions - length, width and height. To calculate for its width, we use the volume formula.
V = l x w x h
From the given, we have:
l = 3w
h = 2 + w
V = 135 ft^3
Substituting the given expressions,
135 ft^3 = 3w (w) (2+w)
135 ft^3 = 6w^2 + 3w^3
Solving for w, we obtain the following values:
w1= 3
w2 = 2.5 + 2.96i
w3 = 2.5 - 22.96i
Since width should not have a negative value, the value of w should be 3 ft.
Answer:
Equation I believe is the answer
let me know if not
Answer:
The answer to your question is: the last option
Step-by-step explanation:
m² - 6m + 6m -36
Simplify like terms m² - 36
Factor (difference of squares) (m + 6) (m - 6)
Answer:
Complementary angles
Step-by-step explanation:
The sum of the 2 angles = 27° + 63° = 90°
This is the definition of Complementary angles