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givi [52]
3 years ago
11

i am thinking of a number. my number is a multiple of 6. what three other numbers must my number be a multiple of?

Mathematics
1 answer:
nignag [31]3 years ago
4 0
Answer : 3, 1 and 2

step by step explanation
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Please help I don’t understand
julia-pushkina [17]
The answer is 32.14
3 0
2 years ago
PLEASE HELP ME!!!
Eddi Din [679]

Answer:

- the pressure will decrease

(volume is doubled ,the pressure reduced by half).

Step-by-step explanation:

P_1 V_1=P_2 V_2

This equation shows that, as volume increases, the pressure of the gas decreases in proportion.

Similarly, as volume decreases, the pressure of the gas increases.

6 0
3 years ago
PLEASE HELP ANSWER CORRECTLY !!!!!!!!!!!!!! WILL MARK BRIANLIEST !!!!!!!!!!!!!!
Nina [5.8K]

Hello, hehelol12.

The length of PR is the same as TR.

Length of PR = 11.

The measure of angle PQR is the same as angle RST.

Measure of angle PQR = 39

I hope this helps you out!

PS. Brainliest would be appreciated. :)

4 0
2 years ago
A fishing boat with two people on it runs out of gas while out in a bay. The people set off an emergency flare from a height of
elixir [45]

Answer:

Step-by-step explanation:

time taken to reach the max height is expressed according to the projectile equation;

tmax = u/g

Given u = 30m/s

g is the acceleration due to gravity = 9.81

t = 30/9.81

t = 3.0secs

hence it will take the flare 3.06secs to reach its maximum height.

Max height = u²/2g

Max height = 30²/2(9.81)

Max height = 900/19.62

Max height = 45.87m

If the people set off an emergency flare from a height of 2 meters above the water, the total height will be 45.87 + 2 = 47.87m

7 0
3 years ago
PLEASE HURRY 50 POINTS Answer Both parts and I will reward Brainliest
vlabodo [156]

We have:

a_1=-3

and:

r=4

so:

$\sum\limits_{n=2}^5\,-3\cdot4^{n-1}=\sum\limits_{n=1}^5\,-3\cdot4^{n-1}-a_1=S_5-a_1=\frac{-3-(-3)\cdot 4^5}{1-4}-(-3)=

=\dfrac{-3-(-3)\cdot 1024}{-3}+3=\dfrac{-3(1-1024)}{-3}+3=1-1024+3=\boxed{-1020}

It is a finite sum, so it is convergent.

6 0
3 years ago
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