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allochka39001 [22]
3 years ago
8

Jim runs off a diving board and lands in the water 3 meters from the end of the board. When he runs at the same speed on a highe

r diving board, he lands in the water 5 meters from the end of the board. Why is this? A. His horizontal velocity was constant. B. Only his vertical velocity affected the time he stayed airborne. C. Running off the higher board he was in the air for a longer time. D. All of these are true.
Physics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

C.

Explanation:

If we look at the equation x(final) = v(initial)*t + x(initial), where v(initial in the x dir.) in the same both times, and x(initial) is 0, we can conclude that t is responsible for the change in x(final).

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Principal of simple machine?​
sergij07 [2.7K]

Answer:

if there is no friction in a simple machine, work output and work input are found equal in that machine

Explanation:

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3 years ago
A kettle of water contains 1.2 kg of water. Calculate how much energy is required to hear it from water at 10 degrees to its boi
Darya [45]

Answer:

450 kJ

Explanation:

Q = mCΔT

where Q is heat (energy),

m is mass,

C is specific heat capacity,

and ΔT is the temperature change.

Q = (1.2 kg) (4180 J/kg/°C) (100°C − 10°C)

Q = 451,440 J

Q ≈ 450 kJ

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What is the minimum diameter necessary for a radio telescope working at f=1×10^10 Hz to be able to separate two objects 1 deg ap
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5 0
2 years ago
a person with a mass of 75kg jumps on the trampoline the trampoline creates a fprce of 375n on them what is the acceleration of
Anarel [89]

Newton's second law allows calculating the response for the person's acceleration while leaving the trampoline is:

            -4.8 m / s²

Newton's second law says that the net force is proportional to the product of the mass and the acceleration of the body

            F = m a

Where the bold letters indicate vectors, F is the force, m the masses and the acceleration

The free body diagram is a diagram of the forces without the details of the body, in the attached we can see the free body diagram for this system

 

               F_t -W = m a

Whera F_t is the trampoline force

Body weight is

                W = mg

We substitute

              F_t - mg = ma

              a =\frac{F_t - m g}{m}

Let's calculate

              a = \frac{375 - 75 \ 9.8 }{75}

              a = -4.8 m / s²

The negative sign indicates that the acceleration is directed downward.

In conclusion using Newton's second law we can calculate the acceleration of the person while leaving the trampoline is

            -4.8 m / s²

Learn more here:  brainly.com/question/19860811

7 0
3 years ago
What's the weight of a 30x30x50 cm body with the density of 1.8/cm cube?
grin007 [14]

Answer:

The weight of the body, W = 793.8 m/s²

Explanation:

Given,

The volume of the body, v = 45,000 cm³

The density of the body, ρ = 1.8 g/cm³

The mass of the body is given by the formula,

                                  m = ρ x v

                                      = 1.8 g/cm³ x 45,000 cm³

                                      = 81,000 g

Hence, the mass of the body is m = 81 kg

The weight of the body,

                                           W = m x g

                                                = 81 kg x 9.8 m/s²

                                                = 793.8 m/s²

Hence, the weight of the body, W = 793.8 m/s²

3 0
3 years ago
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