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allochka39001 [22]
3 years ago
8

Jim runs off a diving board and lands in the water 3 meters from the end of the board. When he runs at the same speed on a highe

r diving board, he lands in the water 5 meters from the end of the board. Why is this? A. His horizontal velocity was constant. B. Only his vertical velocity affected the time he stayed airborne. C. Running off the higher board he was in the air for a longer time. D. All of these are true.
Physics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

C.

Explanation:

If we look at the equation x(final) = v(initial)*t + x(initial), where v(initial in the x dir.) in the same both times, and x(initial) is 0, we can conclude that t is responsible for the change in x(final).

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A current carrying wire is placed in a permanent magnetic field as shown in the diagram below. Determine the direction of the fo
USPshnik [31]

The direction of the magnetic force is to the right.

<h3>What is the magnetic field?</h3>

The magnetic field is the region in space where the influence of the magnet is felt. The magnetic force is always in the direction of the magnetic field.

We can see from the image, that the direction of the magnetic force is to the right.

Learn more about magnetic field:brainly.com/question/14848188

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7 0
2 years ago
a 2.0 kg block slides on the horizontal, frictionless surface until it counters a spring force constant with
icang [17]

Complete question:

a 2.0 kg block slides on the horizontal, frictionless surface until it counters a spring with force constant of  955 N/m. The block comes to rest after compressing the spring a distance of 4.6 cm. Find the initial speed (in m/s) of the block.

Answer:

The initial speed of the block is 1.422 m/s

Explanation:

Given;

mass of the block, m = 2.0 kg

force constant of the spring, K = 955 N/m

compression of the spring, x = 4.6 cm = 0.046 m

Apply Hook's law to determine applied force on the spring;

F = Kx

F = (955 N/m)(0.046 m)

F = 43.93 N

Apply Newton's 2nd law to determine the magnitude of deceleration of the block when it encounters the spring;

F = ma

a = F / m

a = 43.93 / 2

a = 21.965 m/s²

Apply kinematic equation to determine the initial speed of the block;

v² = u² + 2ax

where;

v is the final speed of the block = 0

u is the initial speed of the block

x is the distance traveled by the block = compression of the spring

a is the block deceleration = -21.965 m/s²

0 = u² + 2(-21.965 )(0.046)

0 = u²  - 2.021

u² =  2.021

u = √2.021

u = 1.422 m/s

Therefore, the initial speed of the block is 1.422 m/s

8 0
3 years ago
Human sense impressions are subjective and qualitative
Fittoniya [83]

Answer:trueee

Explanation:

7 0
3 years ago
Which of the following changes will always increase the efficiency of a thermodynamic engine? Choose all correct statements.
Ilya [14]

Answer:B,C,D

Explanation:

Thermodynamic  efficiency is given by

\eta =1-\frac{T_C}{T-H}

\eta efficiency can be increased by Keeping _c constant and increasing T_H

Keeping T_H constant and decreasing T_c

by increasing \Delta T=T_H-T_c

by decreasing \frac{T_C}{T_H} ratio          

5 0
3 years ago
Read 2 more answers
A 1.50-kg iron horseshoe initially at 550°C is dropped into a bucket containing 25.0 kg of water at 20.0°C. What is the final te
Ber [7]

Answer:

Te =  23.4 °C

Explanation:

Given:-

- The mass of iron horseshoe, m = 1.50 kg

- The initial temperature of horseshoe, Ti_h = 550°C

- The specific heat capacity of iron, ci = 448 J/kgC

- The mass of water, M = 25 kg

- The initial temperature of water, Ti_w = 20°C

- The specific heat capacity of water, cw = 4186 J/kgC

Find:-

What is the final temperature of the water–horseshoe system?

Solution:-

- The interaction of horseshoe and water at their respective initial temperatures will obey the Zeroth and First Law of thermodynamics. The horseshoe at higher temperature comes in thermal equilibrium with the water at lower temperature. We denote the equilibrium temperature as (Te) and apply the First Law of thermodynamics on the system:

                             m*ci*( Ti_h - Te) = M*cw*( Te - Ti_w )

- Solve for (Te):

                             m*ci*( Ti_h ) + M*cw*( Ti_w ) = Te* (m*ci + M*cw )

                             Te = [ m*ci*( Ti_h ) + M*cw*( Ti_w ) ] / [ m*ci + M*cw ]

- Plug in the values and evaluate (Te):

                             Te = [1.5*448*550 + 25*4186*20 ] / [ 1.5*448 + 25*4186 ]

                             Te = 2462600 / 105322

                             Te =  23.4 °C    

7 0
3 years ago
Read 2 more answers
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