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maks197457 [2]
3 years ago
10

What forces are those that act on an object causing the net force to be something other than zero?

Physics
1 answer:
Arisa [49]3 years ago
3 0
Gravity is all ways pulling down and the normal force acting on top of the object and for it to have to push or pull to the object
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A potentialiterence of 12 volts is induced across a straight wire 0.20 meters long as it is moved at a constant speed of 3.0 met
shtirl [24]

Strength of the magnetic field: 20 T

Explanation:

For a conductive wire moving perpendicular to a magnetic field, the electromotive force (voltage) induced in the wire due to electromagnetic induction is given by

\epsilon=BvL

where

B is the strength of the magnetic field

v is the speed of the wire

L is the length of the wire

For the wire in this problem, we have:

\epsilon=12 V (induced emf)

L = 0.20 m (length of the wire)

v = 3.0 m/s (speed)

Solving  for B, we find the strength of the magnetic field:

B=\frac{\epsilon}{vL}=\frac{12}{(0.20)(3.0)}=20 T

Learn more about magnetic fields:

brainly.com/question/3874443

brainly.com/question/4240735

#LearnwithBrainly

6 0
3 years ago
A light bulb, a fan, and a tiny speaker are connected to a battery in a series circuit. How will the circuit behave if it is ope
kakasveta [241]
If the circuit is open, then there will be no light or sound. No current will flow and no air will move.
3 0
3 years ago
Read 2 more answers
Suppose two cars depart from a four-way intersection at the same time, one heading north and the other heading west. The car hea
DochEvi [55]

Answer:

Explanation:

The cars are moving away from the intersection at 90° from each other. The motion can be considered a right angled triangle with perpendicular and base being the speeds of the 2 cars. The hypotenuse is the linear distance between them. By Pytagoras theorem:

a) Distance=\sqrt{a^{2}t + b^{2}t  } where a and b are the speeds of 2 cars.

Distance = \sqrt{40^{2}t + 66^{2}t }=77.2t feet/second

b) Time = 2 hours 45 minutes; Convert this into seconds to get 9900 seconds. The distance formula will give distance in feet so we will divide it by 5280 to get miles

Distance= (77.2*9900)/5280 = 144.8 miles

c) 1 Miles = 5280 feet.

5280=77.2t;

Time=68.4 seconds;

The 2 cars are 1 miles apart after 68.4 seconds.

6 0
3 years ago
List at least 3 units of speed circle the unit of speed which is the SI unit
Stells [14]

Answer: SI Unit is meters per second(m/s)

Explanation:

The three units of speed are:

1. meters per second(m/s)

2. kilometers per hour(km/hr)

3. miles per hour(mph)

SI Unit is meters per second(m/s)

6 0
3 years ago
Gold can be hammered into extremely thin sheets called gold leaf. an architect wants to cover a 100 ftà 89 ft ceiling with gold
Ronch [10]

Answer: $62160.534

Explanation:

If the architect needs to cover a 100 ft x 89 ft ceiling with gold leaf sheets with a thickness of 5(10)^{-6}in, he will need  to cover a volume V  as follows (assuming the ceiling has a rectangular shape):

V=(length)(height)(width) (1)

Where:

length=100 ft=1200in

height=89 ft=1068in

width=5(10)^{-6}in

Then: V=(1200in)(1068in)(5(10)^{-6}in)=6408 in^{3} (2)

On the other hand, density \rho is defined as the relation between the mass m of an object and its volume V:

\rho=\frac{m}{V} (3)

As we know the density of gold is \rho=19.32 g/cm^{3} and the volume the architect needs to cover, we can find the mass.

m=\rho V (4)

But first, we have to change the dimensions of the volume we calculated, in order to work with the same units:

V=6408 in^{3}=105.0083cm^{3}

Substituting in (4):

m=(19.32 g/cm^{3})(105.0083cm^{3}) (5)

m=2028.76 g (6) This is the amount of gold keaf sheets the architect needs.

Now, if we know 31.1034768 g cost $ 953, we can find how much 2028.76 g of gold cost:

2028.76 g \frac{\$ 953}{31.1034768 g}=\$62160.534

Therefore, the architect will need $62160.534 to buy the necessary gold to cover the ceiling.

8 0
3 years ago
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