All categories

3 years ago

What forces are those that act on an object causing the net force to be something other than zero?

1 answer:

3 0

Gravity is all ways pulling down and the normal force acting on top of the object and for it to have to push or pull to the object

You might be interested in

Urippe Went to start his lawnmower and was having trouble. At the same moment, Uwi was starting her identical lawnmower in the y

Ivan

Answer:

As each mower presumably needs the same torque to start, and torque is a product of force and moment arm, the longer moment arm of 10.42 cm on Uwi's mower means lower force is required when compared to Urippe's shorter moment arm of 1.35 cm

350 rev/min = 350(2π) / 60 = 36.652 rad/s

36.652 rad/s / 0.294 s = 124.66... 125 rad/s²

a = αR = 125(0.1042) = 12.990... 13 m/s²

a = αR = 125(0.0135) = 1.68299... 1.7 m/s²

I am GUESSING that we are supposed to model these mowers as a uniform disk

τ = Iα

FR = (½mr²)α

F = mr²α/2R

Urippe's pull = (3.56)(0.2041²)(124.66) / (2(0.0135)) = 702.008... 702 N

Usi's pull = (3.56)(0.2041²)(124.66) / (2(0.1042)) = 90.9511...91.0 N

L = Iω = (½(3.56)(0.2041²))36.652 = 2.71771...2.72 kg•m²/s down

using the right hand rule

8 0

3 years ago

How does rhyolite form?

never [62]

Hello There!

I'm pretty sure it is when rhyolitic magma is released.

Hope This Helps You!
Good Luck :)

- Hannah ❤

6 0

3 years ago

Read 2 more answers

You observe a distant galaxy. You find that a spectral line, resulting from an electron transition in hydrogen, is shifted from

alexandr1967 [171]

Answer:

The galaxy is moving away from the observer

Explanation: when a galaxy is moving away from us, the light we percieve from it is "streched". Since the wavelength has an inverse raltionship whith frequency, the longer the wavelength is, the lower the frequency. And lower frequencies correspond to red and infrarred light.

So when we see the light has shifted to the infrarred part of the spectrum, it means the source is traveling away from us, making the light waves we percieve streched and move from visible light to infrarred.

6 0

2 years ago

A plane wave with a wavelength of 500 nm is incident normally ona single slit with a width of 5.0 × 10–6 m.Consider waves that r

kaheart [24]

To solve this exercise it is necessary to use the concepts related to Difference in Phase.

The Difference in phase is given by

$\Phi = \frac{2\pi \delta}{\lambda}$

Where

$\delta =$ Horizontal distance between two points

$\lambda =$ Wavelength

From our values we have,

$\lambda = 500nm = 5*10^{-6}m$

$\theta = 1\°$

The horizontal distance between this two points would be given for

$\delta = dsin\theta$

Therefore using the equation we have

$\Phi = \frac{2\pi \delta}{\lambda}$

$\Phi = \frac{2\pi(dsin\theta)}{\lambda}$

$\Phi = \frac{2\pi(5*!0^{-6}sin(1))}{500*10^{-9}}$

$\Phi= 1.096 rad \approx = 1.1 rad$

Therefore the correct answer is C.

6 0

3 years ago

Explain the relationship between resistance and the velocity of shortening.

butalik [34]

The velocity of shortening refers to the speed of the contraction from the muscle shortening while lifting a load. The relationship between the resistance and velocity of shortening is inverse. The greater the resistance, the shorter the velocity of shortening and the smaller the resistance, the larger the velocity of shortening.

Hopefully this help :)

7 0

3 years ago