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3 years ago

Give me two examples of a pushing force and two examples of a pulling force:

Physics

1 answer:

77julia77 [94]3 years ago

3 0

Answer:

A pushing force example could be a button, like on a keyboard.

Another example would be a piston.

An example of a pulling force could be a lever.

Another example could be rope.

Hope this helps! c:

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1. The resistance of an electric device is 40,000 microhms. Convert that measurement to ohms.

lidiya [134]

Answer:

The answer would be 0.04ohms.

Explanation:

Hopefully this helps

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3 years ago

Read 2 more answers

A woman does 260 J of work to move a table 1.9 m across the floor. What is the magnitude of the force applied by the woman to th

balandron [24]

Answer:136.8N

Explanation:

Work=260joules

Distance=1.9m force=?

Force=work/distance

Force=260/1.9

Force=136.8N

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4 years ago

In an experiment, a ringing bell is placed in a vacuum jar that does not have any air in it. What best describes why the bell is

madam [21]

Answer:

Light does not need a medium to travel travel through, but since waves must have a medium to vibrate, sound is not created where no air is present.

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3 years ago

Witch of the following is not an appropriate unit for power

erica [24]

There are no appropriate units for power on the list you provided

6 0

3 years ago

I need an answer for this plzz!!<br>number 2 <br>anybody can help ??

Anuta_ua [19.1K]

2.1) (i) W = mg downwards
(ii) N = R = Normal Reaction from the ground upwards
(iii) Fe = Force of engine towards the right
(iv) f = friction towards the left
(v) ma = Constant acceleration towards right.
2.2.1)
v = 25 m/s
u = 0 m/s
∆v = v - u = (25 - 0) m/s = 25 m/s
x = X
∆t = 50 s
$a \: = \: \frac{dv}{dt} \: = \: \frac{25 \: \frac{m}{s} }{50 \: s} \: = \: 0.5 \: \frac{m}{ {s}^{2} }$
a = 0.5 m/s².
2.2.2)
F = ma = 900 kg × 0.5 m/s² = 450 N.
2.2.3)
$2ax \: = \: {v}^{2} \: - \: {u}^{2}$
$x \: = \: \frac{ {v}^{2} \: - \: {u}^{2} }{2a} \: = \: \frac{{(25 \: \frac{m}{s})}^{2} \: - \: {(0 \: \frac{m}{s} )}^{2} }{2 \: \times \: 0.5 \: \frac{m}{ {s}^{2} } } \: = \: 625 \: m$
2.3)
Fe = f + ma
Fe - f = ma
For velocity to be constant,
a should be 0, or, a = 0,
Fe = f = 270 N
2.4.1)
v = 0
u = 25 m/s
a = -0.5 m/s²
v = u + at
t = -u/a = -(25)/(-0.5) = 50 s.
2.4.2)
x = -625/(2×(-0.5)) = 625 m.

8 0

3 years ago