write an equation of a line with the given slope and y-intercept. m = –2, b = 4 y = 4x – 2 y = –2x – 4 y = -1/2x 4 y = –2x 4
2 answers:
Answer:
Step-by-step explanation:
Given the values of m=-2, b=4
we have to write an equation of line with above values.
As the general equation of straight line is
where m is the slope and b is y-intercept
Substitute the values of m and b in above equation
m=-2, b=4, we get
which is the required equation of line.
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This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355