Answer:
Life
Explanation:
With out him we wouldn't live
Molecular formula: C10H15Cl5
The molar concentration is 1.11M.
<h3>What is molar concentration?</h3>
The phrase "molar concentration" (also known as "molarity," "amount concentration," or "substance concentration") refers to the amount of a substance per unit volume of solution and is used to describe the concentration of a chemical species, specifically a solute, in a solution. The most frequent measure of molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units. A solution with a concentration of 1 mol/L is referred to as 1 molar, or 1 M.
<h3>Given : </h3>
Volume of the solution = 2L
Mass of glucose given = 200g
Concentration of glucose= ?
<h3>Formula use: </h3>
Molarity = no. of moles of solute / volume of the solution (L)
Moles of solute = given mass of solute / molar mass of the solute
<h3>Solution: </h3>
No. of moles of solute( glucose ) = 200 / 180 = 1.11 moles'
Molarity = 1.11 / 2 = 0.5555 mol L ^(-1)
Therefore, the molar concentration of glucose in the solution = 0.555 mol L ^(-1)
To learn more about molar concentration :
brainly.com/question/15532279
#SPJ4
Answer:
22.4 L at standard temperature and pressure.
Answer:
C) C4H6 - Right answer
Explanation:
Let's combine the Ideal Gases Law with density to get the molecular formula for the unknown gas.
Density = mass / volume
1.06 g /L means that 1.06 grams of compound occupy 1 liter of volume.
P . V = n . R . T
Pressure in Torr must be converted to atm
760 Torr are 1 atm
371 Torr are __ (371 .1)/760 = 0.488 atm
0.488 atm . 1L = 1.06g/MM . 0.082 . 304K
(0.488 atm . 1L) / 0.082 . 304K = 1.06g/ MM
Mass / Molar mass = Moles → That's why the 1.06 g / MM
0.0195 mol = 1.06g / MM
1.06g/0.0195 mol = MM → 54.3 g/m
Now, let's use the composition
100 g of compound have 88.8 g of C
54.3 g of compound have ___ (54.3 . 88.8) /100 = 48 g of C
100 g of compound have 11.2 g of H
54.3 g of compound have __ (54.3 . 11.2)/100 = 6 g of H
48 g of C are included un 4 atoms
6 g of H are included in 6 atoms
